a lot
To standardize 1N H2SO4 with KHP, you would first prepare a solution of KHP of known concentration. Then, titrate the KHP solution with the 1N H2SO4 solution until the endpoint is reached. The volume of H2SO4 used in the titration can then be used to calculate the exact concentration of the H2SO4 solution.
The concentration of hydrogen ions in a 0.1M solution of H2SO4 is 0.2M.
To calculate the percent of a 5 N H2SO4 solution, you need to know the molarity (moles of solute per liter of solution) and the molecular weight of the solute. Once you have that information, you can use the formula: % = (molarity x equivalent weight) / 10. If you provide the molecular weight of H2SO4, I can help you calculate the percent.
To prepare 1N H2SO4 from 95% H2SO4, you would first need to dilute the 95% H2SO4 with water by adding the appropriate amount of water to achieve the desired concentration. To calculate the volume of 95% H2SO4 needed to make 1N solution, you need to use the formula: (Normality of stock solution) * (Volume of stock solution) = (Normality of diluted solution) * (Volume of diluted solution). Adjust the volumes accordingly to prepare the desired 1N solution.
The aqueous solution of H2SO4 is called sulfuric acid.
To prepare a 0.005 M solution of H2SO4 with pH 4, you can first calculate the concentration of H+ ions needed to achieve a pH of 4. Then, use the dissociation of H2SO4 to determine the amount of H2SO4 needed to provide that concentration of H+ ions. Finally, dilute the calculated amount of H2SO4 with water to reach the desired volume of the solution.
First, calculate the mass of the H2SO4 in 16.4 mL of the solution using its density. Then, determine the mass of H2SO4 in the 16.4 mL solution by multiplying the mass of solution by the percentage of H2SO4. Next, convert the mass of H2SO4 to moles using its molar mass to find the number of moles.
To calculate the mass of H2SO4, you first find the moles of H2SO4 using the molarity formula (moles = molarity x volume). Then use the molar mass of H2SO4 (98.08 g/mol) to convert moles to grams. Given that the solution is 5.85 M, you would first calculate moles of H2SO4: 5.85 mol/L x 0.060 L = 0.351 mol. Then convert moles to grams: 0.351 mol x 98.08 g/mol ≈ 34.44 grams of H2SO4.
To prepare a 200ml solution of 0.5M H2SO4, you need to add 12.5ml of 8M H2SO4 and then dilute it up to 200ml. Well, this is how to calculate it, I'll go straight to the equation. use the M1V1 = M2V2 equation, M1 = 8.0 M V1 = Volume needed M2 = 0.5 M V2 = 200 ml 8.0 M x V1 = 0.5 M x 200 ml V1 = (0.5 M x 200 ml)/ 8.0 M = 12.5 ml Cheers :)
The first solution is more concentrated because it contains 6 moles of H2SO4 per one liter of solution. The second solution is less concentrated because it contains 0.1 moles of H2SO4 in one liter. In equal amounts of each example, the first would have more H2SO4.
You'll never reach that because 98% H2SO4 is of lower normality: max. 37 N Density 1840 g solution / L solution Molar mass 98 g/mol H2SO4 concentration 980 gH2SO4 / 1000g solution H2SO4 2 equivalent H+/mol H2SO4 All together making: [1840*(980/1000) / 98 ] * 2 = 36.8N H2SO4 Or the other way 'round: 80N = 40M = 40*98(g/mol) = 3920 gH2SO4/L = 3920/(98*100) = 4000 g (solution)/L , which is more than the most concentrated H2SO4 solution can weight
To prepare a 1N solution of sulfuric acid (H2SO4), you would need to dissolve 49 grams of H2SO4 in enough water to make 1 liter of solution. Since the density of sulfuric acid is around 1.84 g/ml, you would need approximately 26.6 ml of H2SO4 to make a 1N solution.