please give me an answer please
They add up to (1*10)+(4*4)+(3*5) = 41 sides altogether
A quadrilateral has four sides and a pentagon has five. So 2 quadrilaterals and 3 pentagons have 2x4 +3x5 sides = 8 + 15 = 23 sides altogether.
A pentagon has five sides, and a quadrilateral has four sides. So five pentagons and three quadrilaterals have 5*5 + 3*4 sides = 25 + 12 sides = 37 sides.
A pentagon has five sides, and a decagon has ten sides. So 3 pentagons and 5 decagons have (35)+(510) = 65 sides altogether
37 sides
A decagon has ten sides, a quadrilateral has four, an octagon has eight, and a triangle has three. So in 1 decagon, 5 quadrilaterals, 5 octagons, and 5 triangles there are 1*10 + 5*4 + 5*8 + 5*3 = 10 + 20 + 40 + 15 = 85 sides altogether.
A decagon has 10 sides
A decagon has 10 sides
There are 10 sides on a decagon
There are infinitely many polygons which have this property. The easiest to think of is a right triangle. But there are also quadrilaterals, pentagons, etc., that can be constructed that have this property.
A decagon has 10 sides, a dodecagon 12, and a pentagon 5. So 4 decagons, 5 dodecagons, and 3 pentagons have 4*10 + 5*12 + 3*5 sides = 40 + 60 + 15 = 115 sides altogether.
Each decagon has 10 sides, each nonagon has 9 sides and each pentagon has 5 sides. 4 decagons make 40 sides, 2 nonagons make 18 sides and 2 pentagons make 10 sides. When you add them all up together, you get 68 sides in total.