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How much sand required to fill a plot considering compaction percentage?

In construction projects, the process of soil backfilling is crucial for preparing the site for further construction. This guide will outline the steps to calculate the required quantity of soil or sand and the number of trolleys (for material handling) or trucks needed to fill a designated plot. For instance: Given: Plot Length = 20 feet Plot Width = 10 feet Plot Area = Length x Width = 20 x 10 = 200 square feet Depth for filling the plot = 3 feet Volume of soil required to fill the plot = 200 x 3 = 600 cubic feet This calculated volume represents the loose state. The standards for the compaction process are taken into account for filling. The compaction rate indicates that 30% of the original uncompacted soil compacts, resulting in a final compacted soil volume of 70% of the original volume. This means that 1.0 in the original uncompacted state becomes 0.7 in the compacted state. To achieve a fully compacted soil volume of 1.0, we need to fill with 1/0.7 = 1.43 of uncompacted soil. Therefore, the quantity of soil/sand required for the compaction process to fill the plot is calculated as 600 x 1.43 = 857 cubic feet (1.43 is the conversion factor). Next, let's determine the necessary number of Material Handling Trolleys/Trucks: Assuming a trolley with a load capacity of 250 kilograms, capable of carrying 0.15625m3 = 5.51cft of soil (considering dry sand density as 1,600 kg/m3): For 1 cubic meter volume: Number of trolleys required = 857/5.51 = 156 trolleys. Considering a truck can carry 2.265 cubic meters / 80 cubic feet: Number of trucks required = 857/80 = 11 trucks. Please note: The capacity of trucks and carts might vary based on location and brand specifications. In this case, the standard size was not specified and was purchased according to the owner's requirements. However, the volume calculation remains consistent for these computations.

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Rishi Gupta

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1y ago

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