0
so you grabe 3 and you need to mutiply 1 so you can put the problem to 3+0 and 3+0=3.
That how you mutiply 3 in 1
The second way is for small number were you ask yourself how many time can I put 3 in 1.
What else can I help you with?
Solve the equality 3x-1 is?
Baisiclyy 3x-1 3x-1 ____ 9x-1 then the answer is 8x :)
How do you Solve 24 - 3x -27?
24-3x-273x=27+(-24)3x=3x=1
Solve 2y -3x -6?
wat does 2y-3x-6 equal
Solve 5x2 minus 3x minus 1 equals 0?
5*2-3x-1 = 0 10-3x-1 = 0 -3x = 1-10 -3x = -9 x = 3
Can you solve 3x2 2x 1 by factor?
(3x - 1)(x + 1) or (3x + 1)(x - 1) assuming the 1 is negative.
How do you solve math problem 3x-1?
4
How can you solve 3x-4y16 letting y equals -1?
That's not an equation you can solve, since it doesn't have an equal si Assuming you mean: 3x - 4y = 16 For a start, you should replace y with -1. Then solve the resulting equation: 3x - 4(-1) = 16 for x.
How do you solve 1-x3?
1-3x1=3x 1/3=x
Could you Solve the following equation 3x-1 equals 7?
3x-1 = 7 3x = 8X= 8/3 = 2+2/3
How do you solve 3x plus 4 equals 7?
3x + 4= 7 3x= 7-4 3x/3 = 3/3 x=1
How do you solve 2xplus 1 over 3x equals xminus 1 over 5x?
one way to solve an equation in this format, "a/b = c/d", is to multiply both sides by "b"and by "d". You're effectively "cross multiplying" the fractions: (2x + 1) / 3x = (x - 1) / 5x ∴(2x + 1)(5x) = (x - 1)(3x) ∴10x2 + 5x = 3x2 - 3x You can then factor an "x" out of both sides ∴10x + 5 = 3x - 3 And rearrange to solve: ∴10x - 3x = -3 -5 ∴7x = -8 ∴x = -8/7
Solve 3x plus 1 divided by x plus 2x minus 1 divided by 3 equals -3?
(3x + 1) = -3 (x + 2x -1) (3x + 1) = -3 (3x - 1) 3x + 1 = -9x + 3 12x = 2 6x = 1 x = 0.16666666666666666666666666666666666666666666666666666666666666666666
