(xn+2-1)/(x2-1)ExplanationLet Y=1+x2+x4+...+xn. Now notice that:Y=1+x2+x4+...+xn=x2(1+x2+x4+...+xn-2)+1Y+xn+2=x2(1+x2+x4+...+xn-2+xn)+1Y+xn+2=x2*Y+1Y+xn+2-x2*Y=1Y-x2*Y=1-xn+2Y(1-x2)=1-xn+2Y=(1-xn+2)/(1-x2)=(xn+2-1)/(x2-1)
xn+1 = 1/2 ( xn + N/xn )
xn- yn=(x - y)(xn-1 + xn-2y +xn-3y2 +. . .+x2yn-3+xyn-2 + yn-1)
Y=Xn Y/n=X
If by "xn" you mean ax^n then the answer is "a"
This is represented as the algebraic expression xn/n or xn ÷ n.
Yes you (usually) can, though it may depend on your particular C implementation. // A complete (if useless) C program to compute the square root of 2 and then exit. // No headers required. double sqroot(const double s) { double xn = s / 2.0; double lastX = 0.0; while(xn != lastX) { lastX = xn; xn = (xn + s/xn) / 2.0; } return xn; } int main() { double sqrt2 = sqrt(2); return 0; }
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(x23)'=23x22 Generally, (xn)'=n*xn-1
xn = xn-1 - (n + 2).
Deepika padukone belongs to Banglore Karnataka. That is Banglore is her native place . Deepika padukone belongs to Hindu religion.
all branches of sbi in banglore are made core banking system(cbs)...