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# How 30 degree fibers convert compressive force and torsion into tension How 30 degree fibers works in case of torsion For both case compression and torsion investigate if 30 degree is the best. If?

Updated: 9/25/2023 Wiki User

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Q: How 30 degree fibers convert compressive force and torsion into tension How 30 degree fibers works in case of torsion For both case compression and torsion investigate if 30 degree is the best. If?
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### The area of a span that is unaffected by an applied force is?

The line along the length of the beam between areas of tension and compression is called the neutral layer.

### Why bridges have right triangle?

The load distribution is distributed over a certain width vs depth ratio:- as the aspect ration is changed the law of diminishing returns kicks in ie wider the triangle with shorter height will result in excessive tensile force on the bottom chord and higher compressive forces on the two acute sides. It is theoretically considered that the Isosceles triangle best makes use of this optimisation of tension and compressive forces in structures.

### Is a torsion force an internal force?

Yes,torsion(Twist) is an internal force,along with tension(stretch),shear(cut,bend),compression(squeeze).An internal force acts between two parts of something.

### How do you calculate the neutral axis of reinforced concrete slab?

Concrete slabs should be designed to fail under rebar yield as opposed to concrete crushing. So assuming a rebar yielding scenario the first step is to determine the maximum load which can be sustained by the tension rebar as follows, 0.87*Fy gives the failure maximum stress in the steel, which can then be multiplied by the total area of rebar to give the force of the steel in tension. where Fy is the yield strength of the steel. (typical value of Fy is say 500Mpa) Next it is assumed that the slab is in a state of static equilibrium i.e. not accelerating off in any direction! For this to happen the force in the concrete must = the force in the steel, Fst = Fcc = 0.567*Fck*A Fst = force of the steel in tension (calculated above) Fcc = force of concrete in compression = maximum sustainable Force of steel in tension Where Fck = concrete compressive strength, and A = area of a simplified stress block, limiting the depth of the stress block to 0.8x results in ; Fcc = 0.567*Fck*0.8x*B where x = depth to neutral axis B = breadth of slab Rearranging for x gives X = (Fcc/(0.567*Fck*B))/0.8

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