The volume of a cylinder in any position will be the area of the circular end, or top, times the length, or height, along a side. The area of a circle is pi x radius2, where the radius ("r") is half the diameter ("d"), the distance across the circle. Calling the length or height of the cylinder "h", the volume of the cylinder is calculated as: V = (pi x r2)h = (3.1416 x (d/2)2)h Example: What is the volume of cylinder 12" long and 6" across the circular end? V = (pi x r2)h = (pi x (d/2)2)h = (3.1416 x (6/2)2)12 = (3.1416 x 32)12 = (3.1416 x 9)12 = 28.2744 x 12 = 339.3 cubic inches. Be sure to use the same units for r, d, and h. Pi is always 3.1416 (rounded).
Pretty simple. Find the area of the circle. Multiply that by the height of the cyclinder.
You need more information. It all depends on the size of the cylinder
certain fluid at 10 bar is contained in cylinder behind a piston ,the initial volume being 0.05 m3 calculate the work done by the fluid when it expands reversibly i) according to a law P=(A/ V2 ) -(B/ V) ,to a final volume of 0.1 m3 and a pressure of 1bar,where A and B are constants.Answer(19200 j)
Level with the bottom of the fluid's meniscus
A graduated cylinder is simply a beaker with parallel sides and equally spaced volume markings along the side. As the sides are parallel the volume increases proportionately to the level of fluid in the beaker. Equally spaced markings ("graduations") are marked on the side of the cylinder to indicate the volume of fluid to that point.If you are using a graduated cylinder you will notice that the level of fluid (eg water) will seem to cling to the sides of the glass near the edge in a small radius due to the surface tension of the fluid. This radius is called the miniscus. Always read the volume of fluid from the marking at the bottom of the miniscus.
The volume of a cylinder (with a radius of r and a length L ) in the horizontal position filled to a depth (d) can be calculated with the following formula:L((r2)*(arcos((r-d)/r)) - (r-d)*sqrt(2rd-d2))Note: Calculator must be set to work in radians as opposed to degrees
A graduated cylinder is simply a beaker with parallel sides and equally spaced volume markings along the side. As the sides are parallel the volume increases proportionately to the level of fluid in the beaker. Equally spaced markings ("graduations") are marked on the side of the cylinder to indicate the volume of fluid to that point.If you are using a graduated cylinder you will notice that the level of fluid (eg water) will seem to cling to the sides of the glass near the edge in a small radius due to the surface tension of the fluid. This radius is called the miniscus. Always read the volume of fluid from the marking at the bottom of the miniscus.
Check out "horizontal cylindric segment" in Wolfram Alpha Online. That is the correct term for the solid you are looking for. Wolfram Alpha - "The solid cut from a horizontal cylinder of length L and radius R by a single plane oriented parallel to the cylinder's axis of symmetry (i.e., a portion of a horizontal cylindrical tank which is partially filled with fluid) is called a horizontal cylindrical segment."
It depends on what information you have. If the liquid is stored in a container of which the dimensions are known, then you must calculate the volume of the container. You can simply search google for the formulae for the volume of a cube, cylinder, sphere etc. If the dimensions are not known, but the weight and density of the fluid is, then the volume can be calculated as: volume = weight (divided by) density
Capacity of the container = (pi) x (radius of the round end)2 x (height of the cylinder). That's the capacity of the container. If the volume of the fluid in it is really what you want, then you can use the same formula, but instead of the full height of the container, use only the height of the fluid column, i.e. what we professionals would technically refer to as the "depth".
Check out "horizontal cylindric segment" in Wolfram Alpha Online. That is the correct term for the solid you are looking for. Wolfram Alpha - "The solid cut from a horizontal cylinder of length L and radius R by a single plane oriented parallel to the cylinder's axis of symmetry (i.e., a portion of a horizontal cylindrical tank which is partially filled with fluid) is called a horizontal cylindrical segment."
The solution is easy for a vertical 'cylinder' (i.e. a cylinder with its faces at right angles to the direction of gravity, like barrel standing on a horizontal surface. In this case the volume is given by: V=h*(1/2)*pi*(r^2) Where V=Volume, h is the height to which the cylinder is filled, pi is the number Pi (3.142) and r is the radius of the cylinders faces. If the cylinder is vertical (i.e. a barral lying on the gound so that it could easily be rolled away) it gets a bit more tricky: V=l*(pi*r^2/2-r^2*arcsin(1-h/r)-(r-h)*sqrt(h*(2r-h)) Where l is the length of the cylinder. Note: h is always measured from the lowest point of the fluid contained in the cylinder to the the fluid's surface arcsin is the inverse of sin sqrt denotes the squareroot of the following bracket Good luck! felixmschubert@yahoo.de
It is 41.2 millilitres!