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The larger the sample, the lower the % error.. so to reduce a % error, increase your sample size.

Q: How can reduce the percentage error?

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the equipment error is the percentage of uncertainty on the equipment, so for example, a measuring cylinder has the percentage error of around 0.5cm3. The only way I know off to reduce error percentage is to well increase sample size/ volume A etc. as the calculation is something like (equipment error / quantity measured x 100) this would mean that having a higher quantity to measure will therefore decrease percentage error. hope it helps.

Systematic error is the result of complete equilibrium. The method to reduce systematic error is to introduce a proof that demonstrates the group has error in their consensus.

how to reduce the problem of random error and systematic error while doing an experiment

take reading 4 to 5 times, and take its average this will reduce error

Look on the equipment for where it says the plus or minus figure for accuracy (for a burette it is usually + and _ 0.1cm3) divide this by the amount you measured , times 100 to make it a percentage. ---- ---- Percentage Error = Maximum Error / Measured Value X 100 For example.Maximum Error for the following apparatus are:Balance = +/- 0.01Pippette = +/- 0.1 And the Measured value for each are:Balance = 0.15Pippette = 25 Then...the percentage error is:Balance percentage error = 0.01 / 0.15 X 100 = 66.66%Pippette percentage error = 0.1 / 25 X 100 = 0.3% You can now also work out your maximum total error.Maximum total Percentage error = Balance Percentage error + Pippette Percentage errorMaximum total percentage error = 66.66 + 0.4 = 67.06%

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the equipment error is the percentage of uncertainty on the equipment, so for example, a measuring cylinder has the percentage error of around 0.5cm3. The only way I know off to reduce error percentage is to well increase sample size/ volume A etc. as the calculation is something like (equipment error / quantity measured x 100) this would mean that having a higher quantity to measure will therefore decrease percentage error. hope it helps.

Systematic error is the result of complete equilibrium. The method to reduce systematic error is to introduce a proof that demonstrates the group has error in their consensus.

how to reduce the problem of random error and systematic error while doing an experiment

take reading 4 to 5 times, and take its average this will reduce error

Percentage Error is: ~1.4% (1.39049826188%)

Look on the equipment for where it says the plus or minus figure for accuracy (for a burette it is usually + and _ 0.1cm3) divide this by the amount you measured , times 100 to make it a percentage. ---- ---- Percentage Error = Maximum Error / Measured Value X 100 For example.Maximum Error for the following apparatus are:Balance = +/- 0.01Pippette = +/- 0.1 And the Measured value for each are:Balance = 0.15Pippette = 25 Then...the percentage error is:Balance percentage error = 0.01 / 0.15 X 100 = 66.66%Pippette percentage error = 0.1 / 25 X 100 = 0.3% You can now also work out your maximum total error.Maximum total Percentage error = Balance Percentage error + Pippette Percentage errorMaximum total percentage error = 66.66 + 0.4 = 67.06%

Percentage error measures the error in relation to the quantity measured. For example if something weighs 100 grams with a possible error of plus or minus 5 grams, this is an error of 5%

yes, it is. The smaller the measurement, the higher the percentage error.

what is the percent error of 12m

The percentage error in the area of the square will be twice the percentage error in the length of the square. This is because the error in the length affects both the length and width of the square, resulting in a compounded effect on the area. Therefore, if there is a 1 percent error in the length, the percentage error in the area would be 2 percent.

To reduce % error, you may- 1. Take an average over many observations. 2. Use the correct bridge for various measurements of resistance.(see variants of the wheatstone bridge)

A percentage error is 100*(measurement - true value)/true valueThe percentage error is negative if the measured (or calculated) value is smaller that the true value.