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Q: How can the sum of 3 odd numbers is always odd?

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No, the sum of three odd numbers will always be odd.

False. The sum of 3 and 3 is 6. And 6 is even. The product of two odd numbers is always odd. false the sum of 2 odd numbers is always even 3+3=6 5+5=10 103+103=206

That isn't possible. The sum of three odd numbers will always be odd. You can make the sum of 3 prime numbers equal to 32 if one of them is 2 (which is not odd).

I guess you want three odd numbers that, when added, give a sum of 30. That is not possible: if you add three odd numbers, the sum will always be odd.

Any set of three odd integers must be odd - for example, 3 + 5 + 7 = 15. Similarly, the sum of an even number of odd integers added together will always be an even integer.

this would be explained on the basis of two FACTS below....... sum of two odd numbers are always even and sum of to even numbers are also always even then how 6 odd numbers (consider 3 pairs, 9 5 3 1 being odd numbers) can make an odd number 21..!! SO SIMPLE Make your basics strong...

Some odd numbers can be written as the sum of prime numbers. 2 + 3 = 5

No! 1 + 2 + 3 = 6 2 + 4 + 6 = 12 even

The first three odd numbers are 1, 3, and 5. Their sum is 1 + 3 + 5 = 9.

Prime numbers can only be odd, otherwise they'd be divisible by two, and thus not prime. But, as an example: 1 x 3 x 5 x 7= 105. (odd) An odd times an odd is always odd. Since primes are by definition odd, one cannot multiply four prime numbers and get anything other than an odd number, as each step produces an odd number. Thus a multiplicative sum of four primes is always odd. If by a sum you actually mean addition, then anytime you add two odd numbeers you get an even number, so any four prime numbers will give you an even result every time, and one answer is above. I assume you are only dealing with real numbers.Another Answer:Except for the number 2, which is even and prime, all prime numbers are odd. The sum of any two odd numbers is even, and the sum of any two even numbers is even, so the sum of any four odd numbers is also even. There are an infinite number of even numbers that can be written as the sum of four odd prime numbers. The first example is 3 + 5 + 7 + 11 which equals 26 or, in the full case, 3 + 3+ 3 + 3 which equals 18.

9801 * The sum of the first two odd numbers (1+3) is 4, or 22 * The sum of the first three odd numbers (1+3+5) is 9, or 32 * The sum of the first four odd numbers (1+3+5+7) is 16, or 42 * ...and so on So the sum of the first 99 odd numbers, using the pattern above, would be 992 or 9801.

Sorry. No sum of even numbers can be an odd number.

Because the sum of the first N odd numbers is always N squared. Look at 5, 7, and 9. This is 5+7+9 = (1 + 3 + 5 + 7 + 9)-(1+3)= 25-4 =5^2 - 2^2

3 odd numbers can't be equal to 50 because: odd number + odd number = even number even number + odd number = odd number thus, adding 3 odd numbers will always give a sum which is an odd number too even number.

True.

The sum of six odd numbers is never fifteen since 15 is odd and the sum of six even numbers is always even. However if "make" allows products: 1* 1 * 1 * 1 * 3* 5 = 15 ( I used * to mean multiply.)

Just add the end numbers, so 3 + 5 + 4 + 7 = 19 which is odd. Alternatively, ignore even numbers [such as 4], and two odd numbers [3 and 5] added always make an even number [8], which leaves and odd number [7] so the answer will be odd. Example; five hundred different numbers, where 483 are even and 17 are odd, then no matter what the actual 500 numbers are the answer will be odd, as there is an odd [17] quantity of odd numbers.

The sum of two odd numbers is even and the sum of an even number and an odd number is odd.So the sum of three consecutive odd numbers is odd but 270 is even.Ergo there are no three consecutive odd numbers that sum to 270.Three consecutive numbers that sum to 270 are 89, 90, 91.Three consecutive even numbers that sum to 270 are 88, 90, 92.

Let's talk this out and see if we can work it out. The sum of the first N odd integers means, 1+3+5+7+9+11+... Where N is how many odd numbers we're adding. Let's choose numbers for N, and see if we can find a pattern. N=1 --> 1 (sum of the first odd integer) N=2 --> 1 + 3 = 4 (sum of the first 2 odd integers) N=3 --> 1 + 3 + 5 = 9 (sum of the first 3 odd integers) N=4 --> 1 + 3 + 5 + 7 = 16 Do you notice a pattern yet? Take a look at when N = 2, what is the sum? That's right, 4! and when N = 3... the sum is 9. N = 4 the sum is 16.... I see a pattern, do you? Answer: If you don't, you'll notice that the sum of the first N odd integers is always = N2

There are no such answers. The sum of even numbers is even. The sum of odd numbers could be even, but the sum of three consecutive odd numbers is always odd. One could swap the questions to get potentially answerable questions: Sum of 3 consecutive EVEN integers = 150 48 + 50 + 52 = 150 unfortunately, we can already see that if we were to make these odd integers (add 1 to each), we would get 153, not 151. Sum of 3 consecutive ODD integers = 151 49 + 51 + 53 = 153 47 + 49 + 51 = 147 We can see that, whenever we slide our three consecutive integers up one, we raise the value of the sum up 3, and if we jump from odd to odd, or even to even, we raise each integer by 2, so we raise the sum by 6.

6 9 11 23

The prime numbers 3 an 7 are both odd and sum to 10.

Addition of an even number of odd numbers will always equal an even number. Take, for example, 1, 3, 5, 7, the sum of which is 16.It is impossible to add four numbers up to 27 using merely odd numbers.

1, 3, 5, 7, 9, 11 are six consecutive odd numbers whose sum is 36

111 and 201