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this would be explained on the basis of two FACTS below.......

sum of two odd numbers are always even and

sum of to even numbers are also always even

then how 6 odd numbers (consider 3 pairs, 9 5 3 1 being odd numbers) can make an odd number 21..!!

SO SIMPLE

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Q: What 6 digits from the number 9999555533331111 have the sum of 21?

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You can't get six odd numbers to add to an odd number in this Universe, so... a little creative thinking (= "cheating") is needed... 3 + 3 + 3 + 1 + 11 uses 6 digits and the sum is 21... ... if you want to be REALLY "creative", turn one of the nines upside down and you could have 6 + 5 + 5 + 3 + 1 + 1...

21

21

Yes, yes, and no. 3- sum of digits must be multiple of 3. 6- sum of digits must be multiple of 3 and number must be even (multiple of 2). 9- sum of digits must be multiple of 9. (The sum of the digits here is 21.)

If the sum of the digits of the number is a multiple of 3 then that number is divisible by 3. For example: 156351 The sum of the digits is 1+5+6+3+5+1 = 21 which is divisble by 3 156351/3 = 52117

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9 + 5 + 3 + 3 + 1 + 1 = 21

3 + 3 + 3 + 1 + 11 = 21

You can't get six odd numbers to add to an odd number in this Universe, so... a little creative thinking (= "cheating") is needed... 3 + 3 + 3 + 1 + 11 uses 6 digits and the sum is 21... ... if you want to be REALLY "creative", turn one of the nines upside down and you could have 6 + 5 + 5 + 3 + 1 + 1...

It is 399.

21

21

21

That means the number itself is divisible by three. the sum of the digits in 144, for example, is 9. 144 divided by 3 is 48. The sum of the digits in 21 is 3. 21 divided by 3 is 7.If the number is an even number and the sum of the digits is divisible by 3, the number is also divisible by 6. 144 is even and the sum of the digits is divisible by 3, so 144 is also divisible by 6. 144/6 = 24. And finally, if the sum is divisible by 9, the number itself is also divisible by 9. 27 is an example of this.

Yes, yes, and no. 3- sum of digits must be multiple of 3. 6- sum of digits must be multiple of 3 and number must be even (multiple of 2). 9- sum of digits must be multiple of 9. (The sum of the digits here is 21.)

If the sum of the digits of the number is a multiple of 3 then that number is divisible by 3. For example: 156351 The sum of the digits is 1+5+6+3+5+1 = 21 which is divisble by 3 156351/3 = 52117

21 has factors other than 1 and itself, so it is not a prime number. For example, it is divisible by 3. (You can check this by adding the digits of the number: 2 + 1 = 3. If the sum of the digits is divisible by 3, the number is also divisible by 3.) Therefore, 21 is a composite number.

21 is the answer.. dahhh