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How can you find the quadratic formula to solve 3x2 plus 6x equals -2?
Wiki User
∙ 13y ago
The quadratic formula is....
-b +/- sqrt(b^2 -4ac)/2a
in this problem.... ( 3X^2 + 6X + 2 = 0 )
a = 3
b = 6
c = 2
so.....
-6 +/- sqrt(6^2 - 4(3)(2))/2(3)
-6 +/- sqrt(36 -24)/6
-6 +/- sqrt(12)/6
since square root 12 is irrational
-1 +/- sqrt(12)
is the answer
Wiki User
∙ 13y ago
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Solve this quadratic equation using the quadratic formula?
For any quadratic ax2 + bx + c = 0 we can find x by using the quadratic formulae: the quadratic formula is... [-b +- sqrt(b2 - 4(a)(c)) ] / 2a
What is the solution to 4 equals 2b plus b squared?
To find the solution to this equation, you need to rearrange the terms and solve for the variable. 4 = 2b + b^2 can be rewritten as b^2 + 2b - 4 = 0. You can then solve this quadratic equation by factoring, completing the square, or using the quadratic formula.
2x square plus 11x plus 5 equals?
The given expression is a quadratic equation. To find its solutions, we can either factor the equation or use the quadratic formula. However, without an equation to solve or any context, it is not possible to provide a numeric answer.
What is the difference between quadratic formula and quadratic equation?
There are an infinite number of different quadratic equations. The quadratic formula is a single formula that can be used to find the pair of solutions to every quadratic equation.
Why do mathmaticians use the quadratic formula?
To find the roots (solutions) of a quadratic equation.
Solve a2 plus 30a plus 56 equals 0?
a2+30a+56=0 , solve for a Using the quadratic formula, you will find that: a=-2 , a=-28
Solve this quadratic equation using the quadratic formula?
For any quadratic ax2 + bx + c = 0 we can find x by using the quadratic formulae: the quadratic formula is... [-b +- sqrt(b2 - 4(a)(c)) ] / 2a
What is the solution to 4 equals 2b plus b squared?
To find the solution to this equation, you need to rearrange the terms and solve for the variable. 4 = 2b + b^2 can be rewritten as b^2 + 2b - 4 = 0. You can then solve this quadratic equation by factoring, completing the square, or using the quadratic formula.
What is the quadratic formula used for?
The quadratic formula is used all the time to solve quadratic equations, often when the factors are fractions or decimals but sometimes as the first choice of solving method. The quadratic formula is sometimes faster than completing the square or any other factoring methods. Quadratic formula find: -x-intercept -where the parabola cross the x-axis -roots -solutions
2x square plus 11x plus 5 equals?
The given expression is a quadratic equation. To find its solutions, we can either factor the equation or use the quadratic formula. However, without an equation to solve or any context, it is not possible to provide a numeric answer.
How do you factor x2-4x-80 equals 0?
Use the quadratic equation formula to find the solutions to this equation.
What is the difference between quadratic formula and quadratic equation?
There are an infinite number of different quadratic equations. The quadratic formula is a single formula that can be used to find the pair of solutions to every quadratic equation.
What does quadratic equations using the factoring method means?
It means you are required to "solve" a quadratic equation by factorising the quadratic equation into two binomial expressions. Solving means to find the value(s) of the variable for which the expression equals zero.
What does quadratic formula find?
When an equation cannot be solved for "x" to find the zeroes, the quadratic formula can be used instead for the same purpose.
Why do mathmaticians use the quadratic formula?
To find the roots (solutions) of a quadratic equation.
Is there a simple way to solve 7 divided by x minus 5 equals x without having to use the abc-formula it seems there would as it is easy to solve 7 divided by x equals x and with solve is meant find x?
I assume you mean the quadratic formula. Alternative methods include factoring. In this case, it is not easier, since the factors are not obvious. Another alternative method is completing the square, but it isn't really simpler than the quadratic formula, either - at least, not in this case. If you want to solve it by using the graphing calculator: 7/(x - 5) = x x2 - 5x = 7 So graph y = x2 - 5x and y = 7, then find the point of interception where its x-coordinate is the solution of the given equation.
How can you find the complex solutions of any quadratic equation?
I suggest you use the quadratic formula.
