To find the solution to this equation, you need to rearrange the terms and solve for the variable.
4 = 2b + b^2 can be rewritten as b^2 + 2b - 4 = 0.
You can then solve this quadratic equation by factoring, completing the square, or using the quadratic formula.
(a - 2b)(2a - b)
6
2s-2b= a+b+c-2b simplified that would be a+c-b.
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There are no like terms here.
It is: 2b squared
(a - 2b)(2a - b)
=2b
2b=6squared, and 6x6=36
a + 2b = c a = c - 2b
If this was b exponent 2 (squared) or b^2 for the first b, then it is a quadratic expression. b^2 + 2b - 11 = 88 b^2 + 2b - 99 = 0 (b+11)(b-9) = 0 B = -11 or 9
3Mgo+2B
4
(2b - 5)(b + 7)
6
3ab + 3ac + 2b2 + 2bc = 3a(b + c) + 2b(b + c) = (3a + 2b)(b + c)
2s-2b= a+b+c-2b simplified that would be a+c-b.