The following equation must be solved using BEDMAS to get the final answer as 7 using the no. 3 four times:
3/3 + 3 + 3= 1 + 3 + 3= 7
3*3 - 3/3
3³ ÷ 3 x 3 = 27
3*3 + 3/3 = 10
( (3x3) +3 ) /3=4
5*4+3+2
Only four numbers:20233032
2034
1
half of 6 = 3 and 4 times 3 = 12.
There are four of them: 739, 793, 937, and 973 .
25. Using order of operations, the multiplications are completed first, then the addition, so you have 3 x 3 = 9, and 4 x 4 = 16, then add them together 9 + 16 = 25.
3*3+3/3=4