By raising it to a higher position.
10 newton-meters with respect to the ground
The mass' approximate potential energy at four meters is 784 joules.
Calculate the gravitational potential energy between 5 m and 2 m above the ground. If you ignore air resistance, all of that potential energy will be converted to kinetic energy, so that's the answer.
Potential energy is defined as the energy possessed by a body due to its position in the gravitational field. Approximately it will be got by using the expression mgh. m - the mass in kg g-acceleration due to gravity and h - the height above the surface of the earth The other to find the potential energy so precisely is using the expression G Mm/(R+h)2 or replacing GM by gR2 we get mg(R/R+h)2 Any way the details about h is not given. So finding the potential energy will be in complete.
PE=mgh(20 N)(.5 m) = (25 N)xx=0.4 m
20 kilograms and 5 meters? Potential energy = mass * gravitational acceleration * height PE = (20 kilograms )(9.80 m/s2)(5 meters) = 980 Joules of potential energy -----------------------------------------
Potential work = gravitational potential energy = mass x gravity x height = 20 x 9.8 x 10 = 1960 J or 1.96 kJ
10 newton-meters with respect to the ground
The mass' approximate potential energy at four meters is 784 joules.
Calculate the gravitational potential energy between 5 m and 2 m above the ground. If you ignore air resistance, all of that potential energy will be converted to kinetic energy, so that's the answer.
Potential energy is defined as the energy possessed by a body due to its position in the gravitational field. Approximately it will be got by using the expression mgh. m - the mass in kg g-acceleration due to gravity and h - the height above the surface of the earth The other to find the potential energy so precisely is using the expression G Mm/(R+h)2 or replacing GM by gR2 we get mg(R/R+h)2 Any way the details about h is not given. So finding the potential energy will be in complete.
PE=mgh(20 N)(.5 m) = (25 N)xx=0.4 m
100. The amount of energy a roller coaster has is maintained throughout the whole journey. Its the conservation of energy - energy can' t be created or destroyed it can only be transferred. It therefore depends what type of energy you mean in the question. It can have a total of 100 joules meaning yes, anywhere on the roller coaster it will remain as 100 joules however if your saying 100 joules of gravitational potential energy at the top by the bottom of the hill it will have decreased and have been converted into at least 80 joules of kinetic energy leaving 20 joules as gravitational potential energy. Sorry for the poor grammar; just focus on the science. I have an exam on this in two weeks...
To calculate the energy expended in moving a charge through a potential difference, you can use the formula: Energy (E) = Charge (Q) × Potential Difference (V) Given: Charge (Q) = 20 Coulombs Potential Difference (V) = 0.5 Volts Plugging in the values: E = 20 C × 0.5 V E = 10 Joules Therefore, the energy expended in moving a 20 Coulomb charge through a potential difference of 0.5 Volts is 10 Joules.
PE=mgh (20 N)(.5 m) = (25 N)x x=0.4 m
The ball's potential energy will be 19,600 joules.
The formula for the kinetic energy of a body is 1/2(mv2), where m=mass (kg) and v=velocity (m/s). For example, if an object of mass 2 kg is moving at 5 m/s, its kinetic energy is: 1/2 x 2 x 5 x 5=25 Joules (J). The formula for the gravitational potential energy of a body is mgh, where m=mass (kg), g=acceleration due to gravity (m/s2) and h=height of body above the ground (m). Taking g to be 10 m/s2 (for convenience), if an object of mass 2 kg is suspended 20 m above the ground, its gravitational potential energy is: 2 x 10 x 20=400 J