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Q: How can you make 24 using only the following numbers once 7 5 9 8?

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5*4+3+2

3! = 6.

4*3*2 = 24 of them.

5! / 4 - 2 * 3

8

(4+5-6)x8=24

If you want 4-digit numbers, there are 24 of them.

None.

2,5,13,647,809

-9

only using the numbers once

24 numbers.

8 * 1* 2^0 * 4^0=8

Using the combination C(4,3) I got the answer 24. Its either a combination or a permutation.

There are 5*4*3 = 60 such numbers.

(5+7)*(5-3)=12*2=24

No. Not if the numbers are to be used only once. There is only one 5 (or a multiple of 5) in the numbers available. Using times and divide cannot produce any more of them. On the other hand 100 is divisible by 5*5 so at least two fives are required. If the numbers can be used more than once then 2*2*5*5 is one possible solution.

-1230

998,000

24 of them.

None.

1

234, 243, 324, 342, 423, and 432.

-8

1+2+3+4+5+6+7+8+9 = 45