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Q: How can you make four 7's equal 78?

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5.28751 7s equals 37.

7 + 7 + 7/7 = 15

Expressed algebraically, this would equal 7s - 5.

L + S = 72 so L = 72 - S; 4L - 3S = 78 ie 4(72 - S) - 3S = 78 ie 288 - 4S - 3S = 78 ie 7S = 210 so S = 30 and L = 42. And there you have it!

There is one 7s orbital with two sub-orbitals: 7s(+1/2) and 7s(-1/2) . A picture of this 7s orbital is in 'Related links'

4/7 is in its simplest form.

The answer is 7s + 49.

There are four 7s in a deck of playing cards. One 7 of spades, one 7 of clubs, one 7 of hearts, and one 7 of diamonds.

There are 3168 such numbers. 2673 have one 7 459 have two 7s 35 have three and 1 has all four 7s. Numbers with leading 0s are excluded.

The equivalent is 7s+2s = 9s

nothing

7,14,21,28,35

The Arsenal SAM-7S is currently valued at 1500$.

Two electrons (each with opposite spins) in the '7s orbital'

8 / 7 in long division is however many 7s go into 8. so there's 1x 7 in 8 with 1 remainder. For this example, assume every number beyond is a 10, multiplied by the remainder. so, it'd be 7s into 10, which is 1 again. Then 7s into 30, which is 4. Then 7s into 20, which is 2. Then 7s into 60, which 8. Then 7s into 40, which is 5. Then 7s into 50, which is 7. And this is a reoccuring number, making it 1.142857142857 and so on.

7s + 12 = 131 Therefore, 7s = 119 s = 119/7 Therefore, s = 17

You said that 4(2s - 1) = 7s + 12Eliminate parentheses: 8s - 4 = 7s + 12Add 4 to each side: 8s = 7s + 16Subtract 7s from each side: s = 16

No. There are ~37.57 of them.

8

It's 455.

80.

18

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5

14