L + S = 72 so L = 72 - S; 4L - 3S = 78 ie 4(72 - S) - 3S = 78 ie 288 - 4S - 3S = 78 ie 7S = 210 so S = 30 and L = 42. And there you have it!
Expressed algebraically, this would equal 7s - 5.
Puto
7s + 12 = 131 Therefore, 7s = 119 s = 119/7 Therefore, s = 17
2
5.28751 7s equals 37.
7 + 7 + 7/7 = 15
6,**7**78 (700) Hundreds place 6,7**7**8 (70) Tens place
L + S = 72 so L = 72 - S; 4L - 3S = 78 ie 4(72 - S) - 3S = 78 ie 288 - 4S - 3S = 78 ie 7S = 210 so S = 30 and L = 42. And there you have it!
Expressed algebraically, this would equal 7s - 5.
4/7 is in its simplest form.
There are 3168 such numbers. 2673 have one 7 459 have two 7s 35 have three and 1 has all four 7s. Numbers with leading 0s are excluded.
Puto
The answer is 7s + 49.
The equivalent is 7s+2s = 9s
7,14,21,28,35
There can be a maximum of 2 electrons in the 7s orbital, following the Pauli exclusion principle which states that each orbital can hold a maximum of 2 electrons with opposite spins.