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It is NOT rational, but it IS real.


Start with Euler's formula: e^ix = cos(x) + i*sin(x) for all x.

When x = pi/2,

e^(i*pi/2) = cos(pi/2) + i*sin(pi/2) = 0 + i*1 = i

or i = e^(i*pi/2)

Raising both sides to the power i gives

i^i = e^[i*(i*pi/2)] = e^[i*i*pi/2]

and since i*i = -1,

i^i = e^(-pi/2) = 0.20788, approx.

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10y ago

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