You cannot unless you use mathematically invalid procedures. Two of the more common "tricks" are division by zero or equating the negative and postive square roots of a number.
Using faulty logic.
Using a calculator
it is a straight line equation with a slope of 1 and a y intercept of -4
8n = 1 n = 1/8
You can't it equals 2. You can't it equals 2.
a0=(a-1\a-1)=a\a=1
1=6x x=1/6
1/a = 1/b: cross multiplying gives a = b
The difference of algebra and algebra 1 is that in algebra they teach you the basics. For example, they teach you about variables, graphs, how to find slopes. In algebra 1 they start using equations and and teach you how to work longer equations and all that jazz.
Assuming a geometry in which Euclid's Fifth Postulate is considered true... Yes, someone can prove that.
Let a=any integer. If a+(a+1)=2a+1. Any number multiplied by 2 will be even, and if we add 1 to this number, it will be an odd number.
I think there's a typo, otherwise -3 = 1