It is impossible to make 23 from four 9's unless modular arithmetic is involved, in this case in mod 40, 57, 58, 59, 76, 697, 6538. I personally can't see any other way to obtain 23 other than modular arithmetic.
wait not the discription srry
6 of them with a remainder of 4
To make 23 using the numbers 1, 2, 3, and 4, you can use the following equation: ( (4 \times 3 \times 2) + 1 = 23 ). Here, you multiply 4 by 3 to get 12, then multiply that by 2 to get 24, and finally subtract 1 to reach 23.
72
99 plus 9/9 = 100
4! - sqrt(4)*sqrt(4)/4 = 23
23/4 plus 1/4 = 6
1 or 4 , depending on your point of view.
4 and 6/9 so 4 and 2/3 I believe that is correct.
4/9 of 49 = 4*49/9 = 196/9 = 217/9 or 21.77... recurring.
4! - sqrt 4 + 4/4
-3/4