[(√9)! X (√9)!] + 9 + (√9)! = [6 X 6] + 9 + 6 = 51
Note: It can also be done with just three 9s.
[(√9)! x 9] - √9 = [6 x 9] - 3 = 51
You can't use 4 coins to make 16 pounds 51 pence
wait not the discription srry
6 of them with a remainder of 4
72
99 plus 9/9 = 100
4 x 51 = 204
12.75
1 or 4 , depending on your point of view.
4 and 6/9 so 4 and 2/3 I believe that is correct.
0.0784
4/9 of 49 = 4*49/9 = 196/9 = 217/9 or 21.77... recurring.
No, 51 is not a multiple of 4.