(4 + 4 + 4)/4 = 3
use the digit 8 four time to make 89
4 =((4-4)/4)+4 problem solved :D
2 =4/(4+4)*4 problem solved :D
6 =(4+4)/4+4 problem solved :D
9/9 + 99 = 100
88 + 8/8 = 89
7 =(4+4)-(4/4) problem solved :D
88 + 8/888 + 8/8 = 89
A four and a five
55 + 5 x 5 = 55 + 25 = 80
Do the calculation using all digits and round the final answer: 1.3 × 3.04 × 5.46 = (1.3 × 3.04) × 5.46 = 3.952 × 5.46 = 21.57792 Use the digit following the hundredths digit as the deciding digit; the hundredth digit is the second digit after the decimal point so the deciding digit is the third: the deciding digit is 7 which is greater than or equal to 5, so round up: 21.57792 → 21.58 to the nearest hundredth.
150 times ...
NAICS uses a six-digit code to identify particular industries, in contrast to the four-digit SIC code
there are many, many fractions equal to 4/5. because, if you take one number times 4, and use the same number times 5 you will get something equal to 4/5.
no... because you cant multiply four by anything and get one (unless you use fractions, like four times 1/4 would equal 1) but one is a common factor of four
1050 is the four digit number don't know which mathematical procedure to use it took me 5 mins to make a small C# program and ta-da! that's it. :)) cheers
I think you r cheating Mr.Cheater
When you enter a two-digit year value, Excel changes a two-digit year less than 30 to 20xx and a two-digit year of 30 and greater to 19xx. Use four-digit years to ensure that Excel interprets year values the way you intend, if necessary.
There is no difference.
Assuming that the first digit of the 4 digit number cannot be 0, then there are 9 possible digits for the first of the four. Also assuming that each digit does not need to be unique, then the next three digits of the four can have 10 possible for each. That results in 9x10x10x10 = 9000 possible 4 digit numbers. If, however, you can not use the same number twice in completing the 4 digit number, and the first digit cannot be 0, then the result is 9x9x8x7 = 4536 possible 4 digit numbers. If the 4 digit number can start with 0, then there are 10,000 possible 4 digit numbers. If the 4 digit number can start with 0, and you cannot use any number twice, then the result is 10x9x8x7 = 5040 possilbe 4 digit numbers.
how do you write 4 digit numbers with a 0 in ten and hundred place then use the same number to tell which number is larger
Will -22/22 do?