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How can you use the digit 8 four times to make 89?
88 + 8/888 + 8/8 = 89
How many four digits numbers can be formed using 0123456789?
Assuming that the first digit of the 4 digit number cannot be 0, then there are 9 possible digits for the first of the four. Also assuming that each digit does not need to be unique, then the next three digits of the four can have 10 possible for each. That results in 9x10x10x10 = 9000 possible 4 digit numbers. If, however, you can not use the same number twice in completing the 4 digit number, and the first digit cannot be 0, then the result is 9x9x8x7 = 4536 possible 4 digit numbers. If the 4 digit number can start with 0, then there are 10,000 possible 4 digit numbers. If the 4 digit number can start with 0, and you cannot use any number twice, then the result is 10x9x8x7 = 5040 possilbe 4 digit numbers.
How many four digit numbers can you make using the digits 1234?
There are 4 choices for the first digit (1, 2, 3, or 4) since zero cannot be the first digit in a four-digit number. For the second digit, there are 3 remaining choices, for the third digit there are 2 choices, and for the fourth digit, there is only 1 choice left. Therefore, the total number of four-digit numbers that can be formed using the digits 1, 2, 3, and 4 is 4 x 3 x 2 x 1 = 24.
How many combinations can be made out of five digits?
Let's try and figure this one out...First case (the easy one) - We want to use any of the 10 digits to create a 5-digit number. In this case, we have 5 slots and in each slot we can put any of 10 digits.So the answer is 10*10*10*10*10 = 510 = 100,000 combinationsSecond case - We want to create a 5-digit number using any of the 10 digits, but we only want to use each digit once. This turns out to be only a little more difficult.Let's look at each digit individually.First digit - We can use any digit from [0-9], so we have 10 possibilities.Second digit - We can use any digit from [0-9] except for the one used in the first digit, so we now have 9 possibilities.Third digit - We can use any digit from [0-9] except for the ones used in the first and second digits, so we now have 8 possibilities.Fourth digit - As above, except we now have 7 possible choices.Fifth digit - As above, except we now have 6 possible choices.So our final number of combinations is 10 * 9 * 8 * 7 * 6 = 30,240 combinationsSpecial case - What happens if we want to create a number which does not begin with a zero? Well, we can make a simple adjustment to either of the above cases to take care of this. Just observe that the first digit is not limited to 9 possibilities [1-9], not 10.Special first case = 9 * 10 * 10 * 10 * 10 = 90,000 combinationsSpecial second case = 9 * 9 * 8 * 7 * 6 = 27,216 combinations
Use a 3 digit number to form all two digit numbers?
By using the 3 digits of a number we can form 3 different two digit numbers. 3C2 = 3!/[(3 - 2)!2!] = 3!/(1!2!) = (3 x 2!)/2! = 3
How can you use digit 8 four times to equal 89?
89 = 88 + (8 / 8)
Use the digit 4 four times and equal 3?
(4 + 4 + 4)/4 = 3
Use the digit 4 four times to equal 4?
4 =((4-4)/4)+4 problem solved :D
Use the digit 4 four times to equal 2?
2 =4/(4+4)*4 problem solved :D
What is the digit 8 four times to make 89?
To create the number 89 using the digit 8 four times, you can express it as 88 + 8/8. This translates to 88 + 1, which equals 89.
Use the digit 9 four times to make 100?
9/9 + 99 = 100
Use the digit 4 four time to equal 7?
7 =(4+4)-(4/4) problem solved :D
How can you use the digit 8 four times to make 89?
88 + 8/888 + 8/8 = 89
How many strings of four decimal digits a do not contain the same digit twice?
To find the number of strings of four decimal digits that do not contain the same digit twice, we can use the principle of counting permutations. For the first digit, we have 10 options (0-9), for the second digit, we have 9 options (since one digit has already been used), for the third digit, we have 8 options, and for the fourth digit, we have 7 options. Thus, the total number of such strings is calculated as (10 \times 9 \times 8 \times 7 = 5040).
How do I find the appropriate guide page within the emergency response guidebook?
To find the appropriate guide page within the emergency response guidebook, you must use the four-digit identification number or product name of the material.
Which two digit do 45 and 54 use?
A four and a five
How do you use 5 four times to equal 80?
55 + 5 x 5 = 55 + 25 = 80
