answersLogoWhite

0


Best Answer

By using the divisibility rules, I can tell that 864 is divisible by 2, 3, 4, 6, 8 and 9. By dividing those numbers into 864 I can create factor pairs, any of which I can use to start the tree.

864

432,2

216,2,2

108,2,2,2

54,2,2,2,2

27,2,2,2,2,2

9,3,2,2,2,2,2

3,3,3,2,2,2,2,2

User Avatar

Wiki User

โˆ™ 2015-09-13 00:10:07
This answer is:
๐Ÿฆƒ
0
๐Ÿคจ
0
๐Ÿ˜ฎ
0
User Avatar
Study guides

Algebra

20 cards

A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

โžก๏ธ
See all cards

Factoring and Multiples

21 cards

What is the prime factorization of 24

What is the prime factorization of 54

What is the prime factorization of 64

What is the prime factorization of 34

โžก๏ธ
See all cards

Factoring and Multiples

22 cards

What are the particles of matter

Particles of matter move slower as the matter is heated

What are the common factors of 32 and 54

Factors of 325

โžก๏ธ
See all cards

Add your answer:

Earn +20 pts
Q: How can you use divisibility rules to make a factor tree for 864?
Write your answer...
Submit
Related questions

How do you make a factor tree for 7?

You cannot really make a factor tree for 7 because it is already a prime number.


Can you use 1 as a factor when you make a factor tree?

no


Can you make a symmetric factor tree for every composite number?

No you cannot. You might want to try the factor tree for 27.


How do you make a factor tree 293?

293 is prime. No tree.


Can 13 make a factor tree?

No.


How do you make a factor tree for the number 61 and the number 51?

Since 61 is already prime, a factor tree is not necessary. The prime factorization of 51 is 3 x 17, which wouldn't make much of a tree. More like a factor shrub.


How can you make a factor tree with 13?

13 is a prime number. It doesn't have a tree because its only prime factor is itself.


How do you make a factor tree for 991?

991 is already prime. No tree is required.


How do you make a factor tree out of 132?

yes


Explain how you can make more than one factor tree to show the prime factorization for the number 16?

by using a prime factor tree


How do you make a factor tree for 114?

The factor tree is as follows: 114 57,2 19,3,2


How do you make a factor tree for 23?

23 is already prime; it doesn't need a tree.


How can you make a factor tree for 23?

23 is already prime; it doesn't need a tree.


What do you find when you make a factor tree?

prime factors


Is there only one way to make a factor tree?

No.


How do you make a factor tree for 10.91?

Factors, and by extension factor trees, refer to integers, not decimals.


What Is The Factor Tree For 109?

109 109 x 1 This is all there is to the factor tree, because 109 is a prime number. Normally, I wouldn't use 1 in a factor tree, but I do in this case to make it clear that I have done a factor tree, since 109 is only divisible by itself and 1.


How do you make a factor tree for 36?

question:make a factor tree for 36. 6 to the fifth power 6to the fifther power time 6


How do you make a factor tree for 232?

well it would be 51


Make a factor tree for 81?

9x9=81. Proving that one of the factor trees for 81 is 9xp.


What is the GCF of 40 and 35?

All I did was make a factor tree. The GCF (Greatest Common Factor) is 5. :)


What is the factor tree for 77?

The factor tree is this. 77 / \ (7) (11) . . . 7,11 Make sure to box your answer. This was the factor tree for 77.


How do you make a factor tree for 56?

This is a factor tree for 56: 56 28,2 14,2,2 7,2,2,2


What can be made bent laid down and broken but never touched?

Rules, my dear fellow, rules! :D


What is the factor tree of 956?

The factor tree for the number 956 would be written out as 2*2*239. To find the factor tree you can use a factor tree calculator to get the answer you need.