15,3
3,5,3
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27 3,9 3,3,3
9x9=81. Proving that one of the factor trees for 81 is 9xp.
If a multiple of 10 were a factor of 45, then both '10' and the multiple would be factors of 45. Since 10 is not a factor of 45, there is no such number.There are no multiples of 10 that are factors of 45.
There is no multiple of 10 that's a factor of 45.
I can't make the actual lines, but there's a factor tree. 104 2 * 52 2 * 26 2 * 13 2*2*2*13=104