12 = 1
22 = 1 + 3
32 = 1 + 3 + 5
and so on.
The square of the nth whole number is the sum of the first n odd numbers.
The answer is8/[3-(8/3)] = 8/ (1/3) = 8 x 3 = 24Another solution if you can use square roots (the sign V--- will not work here):square root (8x8) x square root (3x3) = 8 x 3 = 24
The square root of 64 is 8 and you can work it out using the square root algorithm.
You can easily work it out. firstly, you know that the even numbers are not prime, so that leaves only ~15 numbers. You can check out each number. [hint you only have to test for factors of a number up to the square root of the number.]
Assuming you mean radical functions, the answer is that you can work with problems that deal with irrational numbers. The classic one was finding the diagonal of a unit square.
The likely square numbers are 36 and 1. (6^2 - 1^2) However, the square numbers 324 and 289 also work. (18^2 - 17^2)
If and only if you are working with a square, you get the square root of the number
the highest sum of the numbers is 17 and the lowest is 1. The only perfect squares in that range are 1,4,9, and 16. That means the following numbers will work: 10,13.18,22,27,31,36,40,45,54,63,72,79,81,88, and 90; that is 16 numbers
The square root of 60 is a single number; you can't have other numbers "between" it. It does work the other way, though - the square root of 60 is between other numbers.
There are 16 different possibility's (you work this out by doing 24, the amount of small squares in it) but only 6 of the have not been rotated or reflected. The real problem is a 3x3 square.
The best way to estimate a quotient using compatible numbers is to first understand how compatible numbers work. They are numbers that are close in value to the actual numbers and are easily added, subtracted or divided.
There is no formula. You have to try multiplying all the numbers until you get 10.
the two numbers in the circles add up to the number in the square box!