"Mean" usually means "average", so you just add the numbers together, then divide by 8.
If the circuit consists of resistors only, you simply add the values of all the resistors, in ohms.
when in series you can use this: R1+R2+R3+enz=you total resistance.and when in parallel you can use this: Req = 1 / (1/R1+1/R2+1/R3+1/R4+enz).If there are 2 resistors in parallel, use Product over sum: Req = R1*R2/(R1+R2).For 3 resistors, a little more tricky: Req = R1*R2*R3/(R1*R2 + R1*R3 + R2*R3). For more than 3, use the general formula above for a quantity of resistors in parallel.
To measure resistance, you could use an ohmmeter. But ohmmeters are not particularly accurate, so other methods are preferable. These include the use of Wheatstone's Bridge (which compares the unknown resistance with known values) or a Ducter (for very low resistances).
constants are values that does not chnage through out the program exceution..
When resistors of the same value are wired in parallel, the total equivalent resistance (ie the value of one resistor that acts identically to the group of parallel resistors) is equal to the value of the resistors divided by the number of resistors. For example, two 10 ohm resistors in parallel give an equivalent resistance of 10/2=5Ohms. Three 60 ohm resistors in parallel give a total equivalent resistance of 60/3 = 20Ohms. In your case, four 200 Ohm resistors in parallel give 200/4 = 50 Ohms total.
Three 8.0-W resistors are connected in parallel. What is their equivalent resistance?
If the circuit consists of resistors only, you simply add the values of all the resistors, in ohms.
It depends upon the resistance values. Series resistance is the summation of all of the resistances, but to calculate the parallel is more complicated. Once the total resistance of each configuration is known, find the total current for each then multiply the current by the source voltage and this will provide the power.
Adding a resistance in parallel to another resistance will reduce the equivalent resistance. Parallel Equation: R1 = 10Ω R2 = 20Ω Req = R1R2/(R1+R2) = (1/R1+1/R2)-1 Req = 10•20/(10+20) = 6.67Ω
when in series you can use this: R1+R2+R3+enz=you total resistance.and when in parallel you can use this: Req = 1 / (1/R1+1/R2+1/R3+1/R4+enz).If there are 2 resistors in parallel, use Product over sum: Req = R1*R2/(R1+R2).For 3 resistors, a little more tricky: Req = R1*R2*R3/(R1*R2 + R1*R3 + R2*R3). For more than 3, use the general formula above for a quantity of resistors in parallel.
To measure resistance, you could use an ohmmeter. But ohmmeters are not particularly accurate, so other methods are preferable. These include the use of Wheatstone's Bridge (which compares the unknown resistance with known values) or a Ducter (for very low resistances).
constants are values that does not chnage through out the program exceution..
When resistors of the same value are wired in parallel, the total equivalent resistance (ie the value of one resistor that acts identically to the group of parallel resistors) is equal to the value of the resistors divided by the number of resistors. For example, two 10 ohm resistors in parallel give an equivalent resistance of 10/2=5Ohms. Three 60 ohm resistors in parallel give a total equivalent resistance of 60/3 = 20Ohms. In your case, four 200 Ohm resistors in parallel give 200/4 = 50 Ohms total.
literals are used to store constant values which are not changed even after program execution
SQL are Database Developers allowing one to produce database tables and values. Ideone is a program that also allows one to change the language as well as the values and program the data into the relevant fields.
Add all the individual resistance values.
It is an circuit that is used to find the value of the resistances. The main principle behind it is the balancing an circuit by means of varying an resistance on connected to an arm of the circuit.When the resistance become equal to the variable resistance no current flows thus we can find the value of the resistance.