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First find the prime factors of all those numbers. Multiply each prime together, using the highest power of the primes if they have exponents.

The primes of the given numbers to their highest power are 22, 32, and 5, so the smallest number divisible by all of them is 180 (22 x 32 x 5).

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13y ago
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Q: How did you get the answer to smallest number that is divisible by 2 3 4 5 6 9 and 10?
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