Want this question answered?
The square of the diagonal minus the square of the height would equal the square of the width. Therefore the square root of the solution to the above problem would be the width
To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).
15 units2
Width is 16.
You can't tell. There are an infinite number of sets of length and width that havea diagonal of 46.The only thing we know for sure is that whatever they are, the square of the lengthand the square of the width add up to 2,116.
The square of the diagonal minus the square of the height would equal the square of the width. Therefore the square root of the solution to the above problem would be the width
To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).
15 units2
Width is 16.
You can't tell. There are an infinite number of sets of length and width that havea diagonal of 46.The only thing we know for sure is that whatever they are, the square of the lengthand the square of the width add up to 2,116.
If d is the diagonal and h is the height Let, l=length of rectangle we have By pythagrous theorem d square= l square + h square therefore l square= d square - h square
The answer can not be calucalted without additional information. If you only know the diagnol measurement, there are an infinite number of possible lengths for the adjoining sides. If this is a question regarding the sizing of TV screens, there are two current formats: standard, where the length to height ratio is 4:3; and letterbox (or widescreen) where the length to height ration is 16:9. Using these ratios and the diagnol length, you can calculate the length and height measurements by establishing: Length = 1.3333 * Height Then: (Diagonal)^2 = (Height)^2 + (1.3333 * Height)^2
If you draw a diagonal in a rectangle you get two equal triangles, each half the area of the rectangle. Area of rectangle is base x height, so half of that is ½ x base x height. QED
First divide the perimeter by 2 then subtract the diagonal from this. The number left with must equal two numbers that when squared and added together equals the diagonal when squared (Pythagoras' theorem) These numbers will then be the length and height of the rectangle.
A rectangle. Height and width.
2*(base) + 2*(height) = perimeter
The one alternative to find the area of a rectangle is when you are given the length of one diagonal and its slope.