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You need to find the area of each of its faces and add them together. An icosahedron may or may not have parallel faces. For example, an icosahedron, in the form of a pyramid with a 19-gon base will have no parallel faces.

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Q: How do I find the lateral area of an Icosahedron and does it have parallel faces?
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Related questions

Lateral area of a prism?

The lateral area of a prism is the sum of the area of the lateral faces


What is the lateral area of a prism?

It is the sum of the area of the lateral faces


What is a lateral area of a prism?

It is the sum of the area of the lateral faces


What two areas are needed to calculate the surface area of a pyramid?

The area of the polygonal base, and the areas of each of its lateral faces (which need not be equal).The area of the polygonal base, and the areas of each of its lateral faces (which need not be equal).The area of the polygonal base, and the areas of each of its lateral faces (which need not be equal).The area of the polygonal base, and the areas of each of its lateral faces (which need not be equal).


Solid figure is the sum of the areas of its lateral faces?

Net but then could be lateral area


Difference between surface area and lateral area?

Lateral area excludes the areas of the top and bottom faces, which are included in the surface area.


When was the surface area formula developed for the triagular prism?

A prism is a polyhedron with two parallel bases bounded by congruent polygons and with lateral faces bounded by parallelograms that connect the corresponding sides of the bases. The height of a prism is any perpendicular line drawn from a point on one base to the other base. If the the bases' shape of a prism is a triangle, we call it a triangular prism (it has 3 faces). The surface area is the sum of the bases' area and the faces' area (lateral area).


Is the surface area of the prism is the sum of the area of the base and lateral faces of the prism?

No, there are TWO bases.


Is the total area of the lateral faces of a pyramid greater than the area of the base?

Yes, it must be.


What is the lateral and surface area of a right prism?

The lateral area of a prism is the sum of the areas of all the lateral faces. A lateral face is not a base. The surface area is the total area of all faces.Lateral Area: The lateral area of a right prism with base perimeter P and height h is L=Ph.Surface Area: The surface area of a right prism with lateral area L and base area is B is S = L + 2B, or S = Ph + 2B.


What is the surface area of a right prism?

The surface area of a right prism is the sum of the areas of all its faces. The formula for calculating the surface area of a right prism is 2 × (base area) + (lateral area), where the base area is the area of the base shape and the lateral area is the sum of the areas of the remaining faces. The lateral area can also be calculated by multiplying the perimeter of the base shape by the height of the prism.


What is the lateral area of a regular quadrangular prism that has a perimeter of 16 cm and a height of 4 cm?

What makes this question tricky to answer is the understanding of the terms. Were the correct terms used in the question, and does the question poster and answer contributor have the same understanding of those terms? Having said that, here goes. A prism is a polyhedron with at least two congruent parallel faces. They are called the bases. The other faces (the "lateral faces") are parallelograms that are formed by lines that connect the corresponding vertices of the two bases. A quadrangular prism has a quadrangular base (such as a rectangle). If the base is some sort of regular polygon, it's called a regular prism. The lateral area of a prism is defined as the total area of the lateral faces. To calculate the lateral area, you multiply the length of an edge by the perimeter of the face that is perpendicular (at right angles to) to that edge. So, assuming the height, 4 cm in this case, is perpendicular to the perimeter, 16 cm, we calculate the lateral area to be 4 x 16 or 64 square centimeters or 64 cm2.