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The side length of a regular octagon whose principal diagonal is 25 feet is 9.57 feet, approx.

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Q: How do I find the length of each side of an octagon 25' across?
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How do you find the length of a side of an octagon?

measure it!


How to find the perimeter of an octagon?

By using the definition of "perimeter": you need to add the lengths of all eight sides. If it is a REGULAR octagon, you multiply the length of any side by 8, since all sides have the same length.


How do you find the sides of an octagon with perimeter?

You say these things to yourself: -- "The perimeter is the distance all the way around the octagon." -- "The octagon has eight sides." -- "So, if it's a 'regular' octagon, then all the sides are the same length, and each side must be 1/8 of the perimeter." -- If it's not a 'regular' octagon, then it has some longer sides and some shorter ones, and the perimeter doesn't help me find the lengths of the sides.


How do you find the perimeter of an octagon if you know the diameter?

I presume by diameter of an octagon you mean the length of the diagonal between opposite vertices of a regular octagon. By completing all the diagonals between opposite vertices of a regular octagon, it divides it up into 8 equal isosceles triangles, with their apexes at the centre of the octagon. The two sides of these isosceles triangles which go from a vertex of the octagon to the centre has a length half that of the diameter. If the centre point of each side of the octagon is joined to the centre of the octagon, each of the 8 isosceles triangles above are split into two (congruent) right angled triangles. The angle at the centre of the octagon of each of these triangles is (360° ÷ 8) ÷ 2 = 22.5°. The side opposite this angle is half the length of the side of the octagon and so the perimeter is 16 times its length. The hypotenuse of the right angled triangles is half the diameter. Thus the trigonometric sine function can be used to find half the octagons side length, and thus its perimeter: sin = opp/hyp → opp = sin x hyp Perimeter = 16 x opp = 16 x (sin 22.5° x diameter/2) = diameter x 8 x sin 22.5° ≈ diameter x 3.061 This can be generalised to any regular even sided polygon if diameter is defined as the length of the diagonal between opposite vertices (which is also the maximum straight line distance between two points on the perimeter): perimeter = diameter x number_of_sides x sin(180° ÷ number_of_sides) As the number of sides increases, "number_of_sides x sin(180° ÷ number_of_sides)" gets closer and closer to π.


How do you get the square meter area of land?

The land you are measuring is probably a rectangle, find the length of 2 sides (that are not directly across from each other) and then multiply them.

Related questions

How do you find the length of a side of an octagon?

measure it!


How to find the perimeter of an octagon?

By using the definition of "perimeter": you need to add the lengths of all eight sides. If it is a REGULAR octagon, you multiply the length of any side by 8, since all sides have the same length.


What is the diameter of an octogon when each side is 18 inches in length?

An octagon is a polygon with 8 sides. To find the diameter of a regular octagon when each side is 18 inches in length, you can use the formula: Diameter = Side length × √(2 + √2) Plugging in the given side length (18 inches): Diameter = 18 × √(2 + √2) ≈ 56.97 inches So, the diameter of the octagon is approximately 56.97 inches.


Find the perimeter of a regular octagon with side length 10ft?

80ft


How do you find the sides of an octagon with perimeter?

You say these things to yourself: -- "The perimeter is the distance all the way around the octagon." -- "The octagon has eight sides." -- "So, if it's a 'regular' octagon, then all the sides are the same length, and each side must be 1/8 of the perimeter." -- If it's not a 'regular' octagon, then it has some longer sides and some shorter ones, and the perimeter doesn't help me find the lengths of the sides.


How many square feet in an octagon if all sides are 8 feet in length?

To find how many square feet are in an octagon you basicly just have to find the area of the octagon in this problem it would be 8x8 to get the answer how to find the answer is that you must first find out how many sides your shape has then multiply your sides length in this case it happens to be 8 for both of the multiples thus 8x8 equals 64.


How do you find the length of a right angle?

the angle is an angle and therefore doesn't have a length. If you want to find the length of the hypotenuse - the leg across from the right angle - it is the square-root of the other two legs each squared.


What is the formula to find the perimeter of an equilateral octagon?

Perimeter = 8 x (length of one side)


How do you find the perimeter of a octagon?

measure each edge and times it by eight.


If an octagon has a circumference of 24 what is its diameter?

I assume that when you say "circumference", you really mean "perimeter" of the octagon. I also assume that by saying, "diameter", you really refer to the widest distance between two points on the octagon. An octagon has 8 sides, so if you divide 24 by 8, then you have 3 units of length per side. Then if you were to draw lines from the center of the octagon out to the ends of the segments of the perimeter, then those lines would be 45 degrees apart from each other. In order to find the "diameter", you need to find the length of one of those lines drawn from the center of the octagon, then double it. To do this, you need to perform some trigonometry. To perform the trig, the easiest thing would be to use a right triangle. By drawing a line from the center of the octagon, perpendicular (at a right angle) to one of the outside segments of the octagon, you bisect the 45 degree angle created by the two lines on either side of it. So then you have created a right triangle inside of the octagon, with a 1.5 unit long side, and an opposing 22.5 degree angle. In this case, you want to find out the length of the longest side of this triangle, which is the hypotenuse. So, the sine of the angle 22.5 degrees is equal to 1.5 units divided by the length of the hypotenuse. If you solve for the hypotenuse, you get 3.92 units, rounded. Double this gives you 7.84 units across the octagon.


How do you find the square footage of a octagon?

An octagon is a square with the corners cut off, so it has 8 equal sides and all angles are the same, like an American Stop sign. If each edge of an octagon is 1 foot, then the area is 4.828 square feet (2+2root2). For an octagon with an edge length of x feet, the area would be 4.828 times x squared.


How do you find the square feet in an octagon?

Assuming it's an octagon with equal sides (s = length of one side in feet) the formula is approximately: Area = 4.8284*(s2)