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Q: How do algebraic operations involving significant figures?

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The least number of significant figures in any number of the problem determines the number of significant figures in the answer.

addition multiplication division subtraction

You make you're calculations using has many (or more) significant figures as requested without any further considerations until you get to the final result... You reduce the final results significant figures to the requested one or add zeros at the end to match it if it is an exact result

The least number of significant figures in any number of the problem determines the number of significant figures in the answer.

The least number of significant figures in any number of the problem determines the number of significant figures in the answer.

The answer depends on what operations were used. There should normally not be more significant figures in the answer than in any of the numbers used in the calculation.

you must know the correct amount of significant figures to round to because it will allow you to eliminate "insignificant" figures, which will shorten things up a bit when recording scientific information involving such figures.

Standard Rounding: 3450 3500 4000 Algebraic Rounding: 3450 3400 3000

4 significant figures.

4 significant figures.

There are four significant figures in .007001

There are four significant figures in 0.1111.

There are two significant figures in 0.025.

Five significant figures.

Three significant figures.

Four significant figures.

Four significant figures.

It has four significant figures

Significant figures

2 significant figures.

It has 5 significant figures.

8 significant figures. Actually, the zeros to the left of the 7 are not significant. There are 2 significant figures.

there are 6 significant figures in 530405000. 5,3,0,4,0, & 5 are the significant figures.

there are 2 significant figures in 21000 2 & 1 are the significant figures.

The significant figures in 0.000042500 are: 0.0000425. So, there are 8 significant figures.