You need three things:
m = mass of the object (in kilograms)
g = gravitational acceleration constant (usually 9.8 m/s^2)
h = height of the object, usually from the ground (in meters)
The gravitational potential energy are these three values multiplied together:
PE = m • g • h
Nobody invented it. The gravitational constant was there - long before the first human being walked on this planet.
You need two points before you can calculate the slope.
"Risk probability" does not quite make sense, perhaps you mean just how to calculate risk. There are many formulas and methods, a lot of them highly complex mathematical models. Risk calculation is an important subset of portfolio theory. For the simplest cases, consider some of the following definitions: * the greatest dive that a stock took over a given historical time period. For example, if stock A dropped 30% maximum over past 5 years before rebounding, and stock B dropped 40% maximum over the same period - then by this metric you can see that stock B is riskier. * standard deviation of the returns over a historical time period. Take as your data set the prices a stock assumed over the last 5 years daily. You can calculate the standard deviation of this data set. The standard deviation is a measure of risk.
A conventional baby scale can be used to calculate urine output. Weight the diaper before putting it on your baby, and then again when it is wet.
The equation for the kinetic energy of a falling object is kinetic energy=1/2 an object's mass multiplied by it's speed squared. From this, we can work out the speed. First you need to know its weight and its kinetic energy. The kinetic energy is obtained by working out it's potential energy before it fell (Potential energy= mass multiplied by gravitational pull multiplied by height. Then, at whatever point during the fall, the decrease in potential energy marks the increase in kinetic energy. From then we work out the speed. Example; An object that weighs 8.1 kilograms is 10 metres above the ground. It's potential energy is therefore 8.1x10(gravitational pull on earth is always 10)x10. So it has a potential energy of 810 joules. it falls 5 metres, so it's potential energy is 8.1x10x5 (405 joules). The total energy, we know, is 810J, so 810-a05=405, giving it kinetic energy of 405J. The kinetic energy formula is then rearranged as speed squared=kinetic energy/ 0.5m. Our equation is therefore speed squared= 405/4.05, so speed squared=100. The square root of 100 is 10 so the speed is 10 metres per second (36 kilometres per hour).
When a ball is dropped, it no longer has potential energy. Before it drops, you can calculate the potential energy (= mgh); to actually measure this, you would have to measure the force, and multiply that by the distance.
The minus sign is required because the gravitational potential is attractive. The sign denotes exergy, giving energy out !
Gravitational potential energy before the ball is bounced which changes to kinetic energy and then to elastic potential energy.
kinetic energy is the amount of energy something has when it is moving. It is measured in Joules (J) it is found by : ke=1/2 mv2`where m=mass in kilograms and v=velocity the gravitational potential energy (gpe) of something before it is dropped = mgh where m=mass in kilograms, g=gravitational field strength (constant at 9.81Nm2) and h =height of object in metres. ke exactly before it hits the ground = gpe before it is dropped from this we can see that 1/2 v2 =gh
No, gravitational portential energy is more with more hight and gravitational kinetic energy is maximum just before reaching the ground.
Gravitational potential energy.
Yes but not both at the same time. All energy is conserved, therefore energy before equals energy after. For example jumping from a ten metre diving board you have gravitational potential energy as you are fulling gravitational potential energy is converted to kinetic energy.
Because gravitational potential energy is defined by g*m*h where g is the gravitational constant 9.8, m is mass, and h is height. With just height and mass, you cannot calculate "wasted energy" by which i assume you mean energy lost to air resistance. However, if you are given the kinetic energy of the object just before it hits the ground, then you calculate the total energy before falling and compare it to the kinetic energy right before hitting the ground. the difference would represent the energy lost to air resistance
the gravitational potential energy of a roller coaster is equal to two things. Not only is it equal to the gravitational potential energy, it is also equal to the kinetic energy at the lowest point of the coaster. the gravitational potential energy can be calculated as: m*g*h where m is mass (kilograms), g is gravity (9.8 m/s^2), and h is height (metres).d the kinetic energy at the bottom of the coaster can be calculated as (m*v^2)/2 where m is mass (kilograms), v is velocity (metres/second).
The water above receives energy as it falls down the short waterfall. This energy was stored as potential energy in the gravitational field of the Earth and came out of storage as the water dropped. This energy which came out of the gravitational field ended up being expressed as the kinetic energy of the water. That is, the water gains kinetic energy as it drops. An ounce of water is going faster when it hits the bottom of the waterfall than it was when it went over the top of the waterfall.
The ball has the highest gravitational potential energy when it is at its highest point in the air, as that is when it has a velocity of zero and is up the highest.
yes it is