You can do the easy bits first. Thus, to calculate 7*5*2, instead of doing 35*2 = 70, you can calculate 7*10 = 70. By itself, the associative property is not as useful as it is in combination with the commutative and distributive properties.
(2+2)+(1+1) 2+2+1+1 Answered my own question :P
I'm sorry but I can't solve that problem. B(
how do you use the properties of similarity to solve practical problem
Yes, but it would be a pointless thing to do. The associative property is much more appropriate.
The associative property means that in a sum (for example), (1 + 2) + 3 = 1 + (2 + 3). In other words, you can add on the left first, or on the right first, and get the same result. Similar for multiplication. How you use this in an equation depends on the equation.
An axiom in algebra is the stepping stone to solving equations. In order to solve and equation you know how to use the commutative, associative, distributive, transitive and equalilty axiom to solve the basic steps. For example: if you want an equation in the form y = mx + b, given 6x - 3y = 9 you must subtract 6x from both sides giving: -3y = 9-6x. Then you divide by -3 to get y = -3 + 2x. But the equation is not in the from y = mx + b. So we use the commutative property to switch the -3 + 2x and make it 2x - 3. Now it become y = 2x -3. and it is in the form y = mx + b. This manipulation could not be perfromed unless tahe student knew the commutative property. Once the axiom is know the algebraic manipulations fall into place.
The commutative property of multiplication states that changing the order of numbers does not change the result or it's value. For example: If 3+2=5 Then 2+3=5 In multiplication: If 3x2=6 Then 2x3=6 There for 3x2=2x3
You cannot solve a set You may be able to solve some questions about properties of a set, or the set and another set. But a set, by itself, is not something that requires or can be "solved".
The answer depends on which properties you have in mind. And since you have not bothered to share that crucial bit of information, I cannot provide a more useful answer.
Quality does not normally play any part in linear equations.