How do you graph 8x plus 5?

Answer 1

use y=mx=b (m being slope and b being y-intercept)

so y=8x+5 and your first coordinate would be (0,5) because if x was 0,

plug it in, [y=8(0)+5] and when simplified y=5 and if x=0 and y=5 well go figure

and for your next coordinates, for ex: x=1 then plug x in [y=8(1)+5] and when

simplified, y=8+5 which in turn equals y=13 so (1,13)