Want this question answered?
Two curves which intersect at right angles, ( the angle between the two tangents to the curve) curves at the point of intersection are called orthogonal trajectories. The product of the slopes of the two tangents is -1.
If two angles are vertical then they are congruent.
Suppose the two masses are m1 and m2. Their initial velocities are u1 and u2 and final velocities are v1 and v2. Then, using conservation of momentum. m1*u1 + m2*u2 = m1*v1 + m2*v2 Both m1 and m2 are given. Their initial velocities u1 and u2 are given and one of the two final velocities v1 and v2 is given which leaves only one unknown. So substitute all those values and calculate away.
When two angles are opposite each other. For example in an "X" the two side openings are vertical and the bottom and top angles are vertical
You first subtract two velocities at two different time intervals. This gives you a difference of velocity. Then you divide this by the time.
well...projectile motion is made of two different motions, or movements- horizontal movement and vertical movement so... i guess that it
well...projectile motion is made of two different motions, or movements- horizontal movement and vertical movement so... i guess that it
well...projectile motion is made of two different motions, or movements- horizontal movement and vertical movement so... i guess that it
By adding the two velocities.
Only if the two velocities are equal in magnitude but in opposite directions.
Two curves which intersect at right angles, ( the angle between the two tangents to the curve) curves at the point of intersection are called orthogonal trajectories. The product of the slopes of the two tangents is -1.
Velocity is a vector quantity(it has a direction). Simply use the vector adding method to combine velocities.
If two angles are vertical then they are congruent.
Suppose the two masses are m1 and m2. Their initial velocities are u1 and u2 and final velocities are v1 and v2. Then, using conservation of momentum. m1*u1 + m2*u2 = m1*v1 + m2*v2 Both m1 and m2 are given. Their initial velocities u1 and u2 are given and one of the two final velocities v1 and v2 is given which leaves only one unknown. So substitute all those values and calculate away.
For different observers (moving at different velocities), the object will have different velocities (relative to the corresponding observer). For one and the same observer, the body will have only one velocity at any given time.
Generally, no.
Sometimes-when there masses are equal.