answersLogoWhite

0

According to ohm's law, voltage in a circuit is directly proportional to current in the circuit and when that proportionality sign is taken off to equals to, a constant is introduced with current and is called resistance. Therefore Voltage in a circuit equals to product of current and resistance in that circuit.

User Avatar

Wiki User

14y ago

What else can I help you with?

Related Questions

What changes the voltage of a current?

First off, voltage and current are two completely different, yet related phenomenons.Kirchoff's law states that Voltage = Current * Resistance (V=IR. So, to change the voltage in a given circuit while keeping current constant, simply change the resistance.Open in Google Docs ViewerOpen link in new tabOpen link in new windowOpen link in new incognito windowDownload fileCopy link addressEdit PDF File on PDFescape.com


Who performed experiments in the 1800s that demonstrated how current voltage and resistance are related?

Georg Ohm, see link to his biography


How can you interconnect two generating station operationg at 60Hz and 50Hz?

Through the use of a high-voltage direct-current link.


How could you calculate the resistance of a circuit?

A variety of techniques can be used. Node-Voltage and Mesh-current (or Loop-current) methods, for example. See related link for examples. If there is a single voltage source in the model, then find the current supplied, and Resistance = Voltage/Current. {R = V/I} You could simulate/ model the circuit on a computer then apply the power profile and a current value will be calculated. Or if you have the circuit working, Place an amp meter into the circuit and measure the current. V/i = resistance.


What happens if you use a fuse that's overrated for voltage but has the correct current rating?

Using a fuse correctly rated for current but "overrated" for voltage does not present a problem. Current ratings are critical safety issues, and fuses should be replaced with those of the same current rating. But using a fuse with an identical current rating but a higher voltage rating is not a problem. The reason for that lies in what the voltage rating of a fuse is. Fuses are given a voltage rating to state a maximum voltage in a circuit that they are designed to protect. And the voltage rating has nothing to do with the "normal" operation of the fuse. The fuse carries current when it operates normally, but when something happens and excessive current flows, the fusible link heats up and opens. This is where the voltage rating comes into play. It is possible that a fuse can arc through when it fails. It is the voltage rating that stands in the way of this. As long as the voltage rating of a circuit is not beyond the voltage rating of the fuse, that fuse will fail safely when it fails. It is acceptable to use a fuse of an equal current rating but a higher voltage rating when replacing a fuse that has failed.


What is the instrument that mesures amper voliteg current?

A multimeter is the instrument used to measure current (amperes), voltage, and resistance. It can be set to measure AC or DC current and voltage, making it a versatile tool for electrical troubleshooting and maintenance.


What happens to an electric current when the wire is made smaller?

Electric current as we usually describe it is the flow of electrons. Current is caused to flow by voltage, which can be looked at as "electrical pressure" that forces electrons to move. Currents can be made smaller or larger by decreasing the voltage across a fixed amount of resistance. As resistance is the quality of "resisting" or "limiting" current flow, we can change resistance to change current. For a give voltage, if we increase the resistance, we can make the current smaller, and if we decrease it, we can make current larger. In electronics, voltage equals current times resistance. E = I x R Also true is that current is equal to voltage divided by resistance. I = E/R As current equals volts divided by resistance, if we change one of them without changing the other, current will change. And in increase in voltage (with no change to resistance) will cause current to go up. The opposite is also true. Also, if we increase resistance (with no change in voltage), current will go down. And the opposite is true here, too.


How fuse can be used in over current protection?

Fuses protect by blowing if too much current flows through the fuse and essentially melts the wire. A very high voltage could cause arcing problems. If you keep the same load then increasing the voltage will increase causes an increase in current. The voltage, current and load (Resistance) are related by Ohm's Law Voltage = Current x Resistance


How are imaginary numbers used in electricity?

The very simplified answer is that imaginary numbers put together with real numbers (to make a complex number) can describe the timing of voltage relative to current, or current relative to voltage, in an AC circuit. Let's say that we're driving an AC electrical circuit with an oscillating current source, and measuring a resulting oscillating voltage. Here's the rub:Purely Real: If you put a resistor in the circuit and measure the voltage oscillations across it, the voltage will be a purely real number. This means that the timing of the voltage peaks will match the timing of the current peaks exactly.Purely Positive Imaginary: Now, put an inductor in the circuit instead of a resistor and measure the voltage oscillations. It will be a purely positive imaginary voltage. This does not mean that the voltage is non-existent (as many people think)! It simply means that the voltage peaks will be one quarter cycle ahead of the current peaks, or 90 degrees ahead. The voltage has physical value. If you were to touch the ends of the inductor, you would still get shocked! The imaginary property just tells you that the timing is ahead by a quarter cycle, that's all--nothing esoteric or "complicated." A good analogy to this would be if you were riding your bicycle side by side with your friend, and you were pedaling at the same rate, BUT your pedal was consistently a quarter turn ahead of his.. Your timing could be considered purely imaginary relative to him (or her).Purely Negative Imaginary: Now, put a capacitor in the circuit and measure the voltage oscillations. It will be a purely negative imaginary voltage, which simply means that the voltage peaks will be one quarter cycle behind of the current peaks, or 90 degrees lagging.Complex: By putting a combination of resistors, inductors, and capacitors in the circuit together, you get a complex voltage, allowing you to get "in between" values. For example, you could carefully size a resistor and inductor, put them in series, and force the voltage peaks to be 45 degrees ahead.Hope this is clear. If it's still cloudy, I'll paste a link in the web link area that has a site out there with an interactive explanation showing how imaginary numbers can be used with complex numbers to represent both size and timing (it's actually my site, but for educational purposes only).While these answers mainly deal with electric power [alternating current], the same concepts apply to waves in general which have a phase difference [difference in timing of peaks and valleys of the waves].Please see the below link for a graph of the fields around current carryingconductors by the formula: w=(z-1)/(z+1), z=x + iy.


What are hvdc links?

the link in hvdc system is a conductor joining rectifier and inverter in series connection.Answer'HVDC' stands for 'high-voltage, direct-current'. A HVDC link is widely-used for interconnecting independent high-voltage a.c. grid systems, such as UK/France. HVDC links eliminate synchronisation problems between the two a.c. grids.


What are depletion and enhancement mosfet?

A depletion MOSFET is a MOSFET that is normally on. It outputs maximum current when the gate-source voltage is 0V. As the gate-source voltage increases, the drain-source channel becomes more resistive and the current decreases. An enhancement MOSFET has the opposite behavior. It is normally off. It outputs no current when the gate-source voltage is 0V. As the gate-source voltage increases, the drain-source channel becomes less resistive and the current increases.


What is the answer the form on the counter at the PokeMart in emerald?

Link Together With All Link Together With All Link Together With All