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How do you Complete the equation of the line through ( 3 and minus 1 ) ( 4 7 )?
Wiki User
∙ 6y ago
Points: (3, -1) and (4, 7)
Slope: 8
Equation: y = 8x-25
Wiki User
∙ 6y ago
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What is the equation of the line that is perpendicular to -x y 7 and passes through -1 -1?
Without an equality sign and not knowing the plus or minus values of y and 7 it can't be considered to be a straight line equation therefore finding its perpendicular equation is impossible.
The line given by the equation y equals 5x minus 2 is perpendicular to what equation?
It is: y = -1/5x-2
What is the general form of a straight line equation perpendicular to 4x plus 3y minus 5 equals 0 passing through a point minus 2 and minus 3 on the line?
Equation of original line is 4x + 3y - 5 = 0 that is, 3y = -4x + 5 or y = -(4/3)x + 5 Slope of original line = -4/3 Slope of line perpendicular to it = 3/4 General equation of perpendicular line: y = (3/4)x + c for some constant c or 4y = 3x + c' The point (-2,-3) is on this line so 4*(-3) = 3*(-2) + c' -12 = - 6 + c' so that c' = -6 The equation of the perpendicular line is 4y = 3x - 6
What is the equation of a line that has zero slope and passes through the origin?
y = 0. You can get this from the slope-intercept equation of the line.
What is the equation of the line that is parallel to the line y x 4 and passes through the point (6 5)?
Without an equality sign and not knowing the plus or minus values of x and 4 the given terms can't be considered to be a straight line equation. Two lines that are parallel to each other will have the same slope but different y intercepts.
What is the equation of the line that is perpendicular to -x y 7 and passes through -1 -1?
Without an equality sign and not knowing the plus or minus values of y and 7 it can't be considered to be a straight line equation therefore finding its perpendicular equation is impossible.
What is the straight line equation passing through the point -2 -3 and perpendicular to the line 4x plus 3y minus 5 equals 0?
3x-4y-6 = 0
What is the equation of the line that passes through (1 2) and is parallel to the line whose equation is 4x y 1 0?
Without an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be a straight line equation. But if you mean 4x+y = 10 then y = -4x+10 and the parallel equation is y = -4x+6
The line given by the equation y equals 5x minus 2 is perpendicular to what equation?
It is: y = -1/5x-2
What is the equation of the vertical line passing through (-4-5)?
What is the equation of the vertical line passing through (-5,-2)
What is an equation of the line that passes through the point (2 1) and is parallel to the line whose equation is 4x 2y 8?
Without an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be an equation but in general parallel equations have the same slope but different y intercepts.
What is the general form of a straight line equation perpendicular to 4x plus 3y minus 5 equals 0 passing through a point minus 2 and minus 3 on the line?
Equation of original line is 4x + 3y - 5 = 0 that is, 3y = -4x + 5 or y = -(4/3)x + 5 Slope of original line = -4/3 Slope of line perpendicular to it = 3/4 General equation of perpendicular line: y = (3/4)x + c for some constant c or 4y = 3x + c' The point (-2,-3) is on this line so 4*(-3) = 3*(-2) + c' -12 = - 6 + c' so that c' = -6 The equation of the perpendicular line is 4y = 3x - 6
How can you write the equation for a linear function if you know only two ordered pairs for the functionDrag tiles to complete the explanation.?
the Equation of a Line Given That You Know Two Points it Passes Through.
How Does a negative slope mean that the line moves up from the left to right?
It means then that the slope of the straight line equation will be minus
What is the equation of a line that passes through a point of minus 1 plus 5 with a slope of 3?
y = 3x+8 which can be expressed in the form of 3x-y+8 = 0
Find the equation of the horizontal line through the point (8,−10)?
The equation of a horizontal line is of the form y=k, where k is the y-coordinate of the point through which the line passes. Therefore, the equation of the horizontal line through the point (8, -10) is y = -10.
What is the equation of a line that has zero slope and passes through the origin?
y = 0. You can get this from the slope-intercept equation of the line.
