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circumference = 2*pi*7 = 43.98229715 arc = (120/360)*43.98229715 = 14.66076572 or 14.661 units rounded to 3 dp
Since the minor arc is 30 degrees, the major arc is 330 degrees (360 - 30). So we have: 330 degrees : arc length 10 30 degrees : arc length x 330/30 = 10/x 11/1 = 10/x x = 10/11 x = 0.9 approximately So the length of the minor arc is approximately 0.9 units.
The answer depends on the information that you have. If the arc subtends an angle of x radians in a circle with radius r cm, then the arc length is r*x cm.
A whole circle is 360 deg so the major arc is 360-120 = 240 degrees.
A+ 13.03^.^
find the arc length of minor arc 95 c= 18.84
It will be 1/3 of the circle's circumference
Arc length = pi*r*theta/180 = 17.76 units of length.
5.23
13.08
An arc length of 120 degrees is 1/3 of the circumference of a circle
19.28
circumference = 2*pi*7 = 43.98229715 arc = (120/360)*43.98229715 = 14.66076572 or 14.661 units rounded to 3 dp
It is: 72-lenghth of major arc = length of minor arc
Since the minor arc is 30 degrees, the major arc is 330 degrees (360 - 30). So we have: 330 degrees : arc length 10 30 degrees : arc length x 330/30 = 10/x 11/1 = 10/x x = 10/11 x = 0.9 approximately So the length of the minor arc is approximately 0.9 units.
The answer depends on the information that you have. If the arc subtends an angle of x radians in a circle with radius r cm, then the arc length is r*x cm.
I'm assuming that "c" is short for "circumference". The length of an arc is (circumference)*(360/angle). So the length of an arc in a circle with circumference length of 18.84 is 6782.4/angle, where the angle is measured in degrees.