How do you Integrate the following S4x3-2x2 x-1dx in Calculus?

Answer 1

∫(4x3 - 2x2 + x - 1) dx

You can integrate this by taking the antiderivative of each term. Each of these terms is in the format axn, the antiderivative of which is axn-1/n:

= ∫(4x3)dx - ∫(2x2)dx + ∫(x)dx - ∫(1)dx

= x4 - 2x3/3 + x2/2 - x + C