If n + 7 = 12, then n = 12 - 7
(n/(18*6))/n4=(n/108)/n4 ;Multiply 18 and 6(n/108)*(1/n4) ;Multiply by the reciprocal of n4, which is just 1 over n4n/(n4*108) ;The n4 will go in the bottom of the fraction1/(108n3) ;n over n4 will give you 1 over n3
3n and n = 4? 3n ( the four replaces the n 3(4) = 12 =======
If: 12-7n2 = 0 Then: n = square root of 12/7
16
12+4n = 2n12+4n-4n = 2n-4n12 = -2n-1/2(12 = -2n)-6 = n
10n+12 = 14n-12 10n-14 = -12-12 -4n = -24 n = 6
n =33
The product of four and a number would be algebraically written as 4n, or whatever variable equals the number. In this case, n = number. It would not be written n4, nx4, 4xn, 4*n or n*4, although n4 and the ones with stars may be accepted by a teacher.
The answer is n = 5.
2n/3 = 4 2n = 3*4 2n = 12 n = 6 :)
To solve the equation n + 3x6 = 30, first calculate 3x6, which equals 18. Then subtract 18 from both sides of the equation to isolate n. Thus, n = 30 - 18, which simplifies to n = 12.