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You can only add a 3x3 matrix to another matrix of the same size. The reuslt is a 3x3 matrix where each element is the sum of the elements in the corresponding positions in the two summand matrices.

Symbolically,

if A = {aij} and B = {bij} then A + B = {aij + bij}

where i=1,2,3 and j = 1,2,3

Q: How do you add 3 x 3 matrix?

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Yes it is possible. The resulting matrix would be of the 2x3 order.

It will be a 2 x 5 matrix.

That's a special calculation done on square matrices - for example, on a 2 x 2 matrix, or on a 3 x 3 matrix. For details, see the Wikipedia article on "Determinant".

taking an example of matrix x ,we find whether this matrix is transitive or not: x=[1 1 0 ;1 0 1;1 0 1] m=1; for i=1:3 for j=1:3 if x(i,j)==1 for k=1:3 if x(j,k)==1 if x(i,k)~=1 m=0; end end end end end end if m==1 disp('Given matrix is Transitive') else disp('Given Matrix is not Transitive') end

A rectangle containing numbers are called "matrix" (1 0 0 1) (3 4 8 0) is a 2 x 4 matrix a SQUARE containing numbers is a n x n matrix, or square matrix (1 0) (5 6) is a square matrix (1) is a square matrix

Related questions

3 x 3 matrix

3x1 matrix

No.Two matrices A and B can be added or subtracted if and only if they have the same number of rows and columns. That is a 3 x 2 matrix can be added or subtracted only with another 3 x 2 matrix.

Yes it is possible. The resulting matrix would be of the 2x3 order.

The first matrix has 3 rows and 2 columns, the second matrix has 2 rows and 3 columns. Two matrices can only be multiplied together if the number of columns in the first matrix is equal to the number of rows in the second matrix. In the example shown there are 3 rows in the first matrix and 3 columns in the second matrix. And also 2 columns in the first and 2 rows in the second. Multiplication of the two matrices is therefore possible.

No. Matrix addition (or subtraction) is defined only for matrices of the same dimensions.

No, but it can be multiplied: The new matrix is 3x3. EG: 100100 100 200 010010 x 010 = 020 001001 001 002 100 010 001

No it can't !!!Matrix property: A matrix A of dimension [nxm] can be multiplied by another B of dimension [ txs] m=t.m=t => there exist a C = A.B of dimension [nxs].Observe that given [3x5] and [3x5], 5!=3(not equal to) so you can't!

It will be a 2 x 5 matrix.

The answer is yes, and here's why: Remember that for the eigenvalues (k) and eigenvectors (v) of a matrix (M) the following holds: M.v = k*v, where "." denotes matrix multiplication. This operation is only defined if the number of columns in the first matrix is equal to the number of rows in the second, and the resulting matrix/vector will have as many rows as the first matrix, and as many columns as the second matrix. For example, if you have a 3 x 2 matrix and multiply with a 2 x 4 matrix, the result will be a 3 x 4 matrix. Applying this to the eigenvalue problem, where the second matrix is a vector, we see that if the matrix M is m x n and the vector is n x 1, the result will be an m x 1 vector. Clearly, this can never be a scalar multiple of the original vector.

That's a special calculation done on square matrices - for example, on a 2 x 2 matrix, or on a 3 x 3 matrix. For details, see the Wikipedia article on "Determinant".

taking an example of matrix x ,we find whether this matrix is transitive or not: x=[1 1 0 ;1 0 1;1 0 1] m=1; for i=1:3 for j=1:3 if x(i,j)==1 for k=1:3 if x(j,k)==1 if x(i,k)~=1 m=0; end end end end end end if m==1 disp('Given matrix is Transitive') else disp('Given Matrix is not Transitive') end