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What else can I help you with?
How many positive two-digit integers is the ones digit greater than twice the tens digit?
4
How many 4-digit even integers are there?
There are 4500 such numbers.
How many 2 digit positive integers are divisible by 4?
22 of them.
What is 8 5 4 9?
Four random, positive, one-digit integers.
How many one digit integers are there?
There are 10 one digit positive integers (0 - 9) and 9 one digit negative integers (-9 to -1) making 19 in all.
How may two digit-numbers contain the digit 4?
18 positive integers and 36 integers (negative and positive)
How do you add integers if they are the same sign?
Add the magnitudes of the integers (-4 has a magnitude of 4), then take the sign to the answer.
How many positive two-digit integers is the ones digit greater than twice the tens digit?
4
How many 4-digit even integers are there?
There are 4500 such numbers.
How many 2 digit positive integers are divisible by 4?
22 of them.
How many three digit integers can be divided by 4 to produce a new integer with same ten digit and unit digit as original integer?
400/4= 100 and 800/4=200
What is 8 5 4 9?
Four random, positive, one-digit integers.
How many one digit integers are there?
There are 10 one digit positive integers (0 - 9) and 9 one digit negative integers (-9 to -1) making 19 in all.
The sum of four consecutive even integers is the same as the least of the integers Find the integers?
-4, -2, 0, and 2 are the four consecutive even integers. When you add them up they equal -4.
How many 4-digit positive integers are there?
from 1000 to 9999, ie 9999 - 999 = 9000
How many 1-digit integers are there such that product of their two digit is 24?
-23
How many 4 digit numbers can you make that contain 5?
There is a clever but tricky way to solve this. If we have to find the number of 4-digit integers that contains at least one 5, we can also find the number of all the 4-digit integers and the number of integers that do not contain any 5's and subtract it from the first number. This is called complementary counting.So, first of all, we must find the number of 4-digit numbers there are. There are 9000 of them.Now, we find the number of 4-digit integers without 5's. By thinking a little bit, we see the first digit must be from 0~9 excluding 5. That is a total of 9 numbers. This is the same for the next three digits. Therefore, there are 94 = 6561 4-digit numbers without a 5.Finally, we can subtract. 9000 - 6561 = 2439
