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How do you add together 1666 and 1999 in two different ways using Roman numerals?
The real rules governing the original Roman numeral were changed during the Middle Ages presumably to make the system more compatible with the Hindu-Arabic numeral system that was slowly being introduced into Western Europe at the time. So as a consequence of these changes nowadays we would convert 1999 into Roman numerals as MCMXCIX which inhibits their ability to interact sensibly with other numerals.
But there is historical evidence to suggest that the ancient Romans would have worked out the equivalent of 1999 on an abacus counting device as MDCCCCLXXXXVIIII and then systematically reduced them to IMM in written format thus facilitating the speed and ease of addition as follows:-
MDCLXVI+IMM = MMMDCLXV => 1666+(2000-1) = 3665
Alternatively:-
MDCLXVI+MDCCCCLXXXXVIIII = MMMDCLXV => 1666+1999 = 3665
Values: M=1000 D=500 C=100 L=50 X=10 V=5 and I=1
Note: 5*I=V 2*V=X 5*X=L 2*L=C 5*C=D and 2*D=M
QED by David Gambell
What else can I help you with?
How would you actually add together 1666 and 1999 in two different ways entirely in Roman numerals throughout both calculations with explanations?
See answer to question: ' How do you add together 1666 and 1999 in two different ways using Roman numerals'
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