The answer depends on what it is.
2 and 2 0 and 0
They draw lines such as when you would try to figure out 7x6 you would make | for the 7 and _____ this way for the 6 then make half like circles on all 4 corners and count as you write them down. The answer is write every time but you can only do up to 2 digits.
Remember the commutative property of multiplication: 4 x 2 is the same as 2 x 4. The number of digits in a product can not exceed the number of digits in the multiplier and multiplicand: the product of 23 X 234 is five digits or less.
The best way to break down a number (from the perspective of arithmetic!) is to write it as a product of its prime factors. For instance, 24 = 2 x 3 x 4 where x is the multiplication operator and of course 2, 3, and 4 are all prime numbers.
When multiplying numbers with different numbers of significant digits, the result should have the same number of significant digits as the least precise measurement. Count the number of significant digits in each number, perform the multiplication as usual, and then round the result to the least number of significant digits used in the calculation.
100,000,000 = 9 digits, unless you're going to get sassy and say that 'create' can also mean calculate the number through f.ex. multiplication. Then you'd quickly be down to at least 3 digits, as 10^9 = 100,000,000 = 9 digits. Whether or not 2 digits would be possible I am not entirely sure, then I guess you'd have to enter the world of symbols and letters (thus loosening the definition of 'digit' as well).
Using the digits, we can make 81 x 62 equals 5022, which is the largest possible product.
If you mean, "What is the largest number of digits possible in the product of two 2-digit numbers" then 99 * 99 = 9801, or 4 digits. Anything down to 59 * 17 = 1003 will have 4 digits.
That rounds down to 34.
A number with more than 2 digits must be at least 100. Any two numbers of this kind will give an answer that is at least 10000. So there are no ways to make 144 with multiplication of numbers with more than 2 digits.
To find the number of three-digit positive integers with digits whose product is 24, we can break down 24 into its prime factors: 2 x 2 x 2 x 3. The possible combinations for the three digits are (2, 2, 6), (2, 3, 4), and (2, 4, 3). These can be arranged in 3! ways each, giving a total of 3 x 3! = 18 three-digit positive integers.
69, cheeky!