Measuring the current in each phase (or do you mean 'line'?) will not give you sufficient information to work out what you are asking for.
In a three-phase 225 amp panelboard, each phase will carry 225 amps. This means that the total current flowing through the panelboard is distributed evenly across the three phases, allowing for a maximum of 225 amps on each phase at a time.
In a standard 3 phase system in North America, 7kVa would be equivalent to 19.5 amps on each phase. The equation is: 7kva*1000/208v/1.73=19.45 amps (3 phase)
In a three phase 225 amp panel, there would be a total of 225 amps available for each phase, making it a total of 675 amps for all three phases combined. This means that you could have up to 225 amps of current flowing through each phase simultaneously.
For a balanced load, you don't have to worry about phase values when you want to determine the power (or, in this case, the energy), whether delta or wye. Rather, you always use line values:P = 1.732 VL IL cos (phase angle)For an unbalanced load, however, you need to measure the phase voltage and phase current and power factor for each of the three phases, and add them together:P = [VpIp cos (phase angle)]phase A +[VpIpcos (phase angle)]phase B+[VpIp cos (phase angle)]phase CTo then calculate the energy expended in kilowatt hours, you need to multiply the total power (as calculated above), expressed in kilowatts, by the time for which the load is operating, expressed in hours.
To calculate the current draw, use the formula: Current (A) = Power (W) / (Voltage (V) * √3). Plugging in the values, we get Current = 30000W / (208V * √3) ≈ 78.7A. So, a 30KW strip heater operating at 208 volts 3-phase would draw approximately 78.7 amps.
Still 30 amps, but at 240 V you'll have twice the watts that you would on a 120 V, 30 amp circuit, and after all, watts are what actually does the work.
Yes, for a 15HP 3-phase 415V AC motor, each phase will draw approximately 26 Amps of current when running under normal operating conditions. This results in a total current draw of 26 Amps per phase for the motor.
For a single phase circuit, the equation you are looking for is I = W/E. Amps = Watts/Volts.
Each hot leg to the neutral wire of the service has the ampacity of 200 amps, that is why 3/0 wire is required. A 3/0 copper wire with an insulation factor of 90 degrees C is rated at 210 amps.
thong each wire using amp meter
On a 50 amp 3 phase connector, you can pull 50 amps per leg. This means that each of the three phases can carry up to 50 amps individually, resulting in a total capacity of 50 amps per leg.
You have to know the power loading and phase angle (or power factor) between each pairh of the phases, otherwise you could be making serious errors.