Answer: 'm' times. Examples: If m=2, Then m2 = (2x2) = 4 -> 4-2-2 = 0 (So subtracted TWICE) If m=4 Then m2 = (4x4) = 16 -> 16-4-4-4-4 = 0 (So subtracted FOUR TIMES) This works no matter how large the number is!
Yes
Momentum (p) is mass (m) times velocity (v), so p = mv
Multiply m by m.
The question is open to multiple interpretations but I think you mean [(-2m)^4] x (n^6)^2 = [(-2)^4](m^4)(n^12) = 16(m^4)(n^12) or 16 times m to the 4th power times n to the 12th power.
From that information, we can't calculate the mass of the object. But we can calculate the strength of the force that was used to move it. Work = (force) times (distance) 372 = (force) times (16) Force = 372 / 16 = 23.25 newtons
Joseph M. O'Donnell has written: 'The canons of the First Council of Arles, 314 A.D' -- subject(s): Arles, Council of (1st : 314)
You can solve this for p:2m + 2p = 162p = 16 - 2mp = 8 - mIf you supply a value for "m", you can then calculate p.You can solve this for p:2m + 2p = 162p = 16 - 2mp = 8 - mIf you supply a value for "m", you can then calculate p.You can solve this for p:2m + 2p = 162p = 16 - 2mp = 8 - mIf you supply a value for "m", you can then calculate p.You can solve this for p:2m + 2p = 162p = 16 - 2mp = 8 - mIf you supply a value for "m", you can then calculate p.
Answer: 'm' times. Examples: If m=2, Then m2 = (2x2) = 4 -> 4-2-2 = 0 (So subtracted TWICE) If m=4 Then m2 = (4x4) = 16 -> 16-4-4-4-4 = 0 (So subtracted FOUR TIMES) This works no matter how large the number is!
Yes
2
8.15
Momentum (p) is mass (m) times velocity (v), so p = mv
Multiply m by m.
The question is open to multiple interpretations but I think you mean [(-2m)^4] x (n^6)^2 = [(-2)^4](m^4)(n^12) = 16(m^4)(n^12) or 16 times m to the 4th power times n to the 12th power.
well you calculate the M with the I with the A and then you get your answer but its MXIXA
What does m times m times m mean?