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What is M to the fourth power Times n to the fourth power?
m4n4
X to the third power times x to the fourth power?
X to the 7th power. X^m*X^n=X^m+n That means when you multiply variables with the same base, you add the exponents.
What is the fourth root of 125 m times the fourth root of 35?
8.13288 (rounded)
How would you write an verbal expression for 4m to the fourth power?
Four times a variable, named m, multiplied by itself four times. Technically (or pedantically) it is multiplied three times but that is one of the oddities of verbal expressions.
How do you solve M to the power of 4 times N to the power of 5 minus M to the power of 20 times N to the power of 21 m4 n5 - m20n21?
m^4 n^5 - m^20 n^21
What is M to the fourth power Times n to the fourth power?
m4n4
X to the third power times x to the fourth power?
X to the 7th power. X^m*X^n=X^m+n That means when you multiply variables with the same base, you add the exponents.
What does m to the third power mean?
Well, hello there! When we see "m to the third power," it means we are multiplying 'm' by itself three times. So, if we have m x m x m, that's what m to the third power represents. It's like painting a lovely little trio of 'm's dancing together on our canvas of mathematics.
What is the answer to -2m to the fourth power times n to the 6thpower to the 2nd power?
The question is open to multiple interpretations but I think you mean [(-2m)^4] x (n^6)^2 = [(-2)^4](m^4)(n^12) = 16(m^4)(n^12) or 16 times m to the 4th power times n to the 12th power.
What is m to the third power plus 125n to the third power?
m3 + 125n3 = (m + 5n)*(m2 - 5mn + 25n2)
What is the fourth root of 125 m times the fourth root of 35?
8.13288 (rounded)
How would you write an verbal expression for 4m to the fourth power?
Four times a variable, named m, multiplied by itself four times. Technically (or pedantically) it is multiplied three times but that is one of the oddities of verbal expressions.
How do you simplify six to the second power times six to the third power?
To simplify (6^2 \times 6^3), you can use the property of exponents that states (a^m \times a^n = a^{m+n}). In this case, you add the exponents: (2 + 3 = 5). Therefore, (6^2 \times 6^3 = 6^5).
Subtract one fourth from 8 times m?
8m - 1/4
How do you solve M to the power of 4 times N to the power of 5 minus M to the power of 20 times N to the power of 21 m4 n5 - m20n21?
m^4 n^5 - m^20 n^21
What is the fourth index law?
It is not possible to answer the question because different books number number the laws differently.
What does M to the second power equal?
The "second power" means squared. "Squared" means multiplied by itself. Thus M to the second power = M times M.
