m^4 x m^3 = m^7
Using a numerical example, 2^4 x 2^3 = 16 x 8 = 128 = 2^7
m4n4
X to the 7th power. X^m*X^n=X^m+n That means when you multiply variables with the same base, you add the exponents.
8.13288 (rounded)
Four times a variable, named m, multiplied by itself four times. Technically (or pedantically) it is multiplied three times but that is one of the oddities of verbal expressions.
m^4 n^5 - m^20 n^21
m4n4
X to the 7th power. X^m*X^n=X^m+n That means when you multiply variables with the same base, you add the exponents.
Well, hello there! When we see "m to the third power," it means we are multiplying 'm' by itself three times. So, if we have m x m x m, that's what m to the third power represents. It's like painting a lovely little trio of 'm's dancing together on our canvas of mathematics.
M to the third power, expressed mathematically as M³, means M multiplied by itself two more times, resulting in M × M × M. This operation raises the variable M to the exponent of three. The value of M³ will depend on the specific value of M.
The question is open to multiple interpretations but I think you mean [(-2m)^4] x (n^6)^2 = [(-2)^4](m^4)(n^12) = 16(m^4)(n^12) or 16 times m to the 4th power times n to the 12th power.
m3 + 125n3 = (m + 5n)*(m2 - 5mn + 25n2)
8.13288 (rounded)
Four times a variable, named m, multiplied by itself four times. Technically (or pedantically) it is multiplied three times but that is one of the oddities of verbal expressions.
To simplify (6^2 \times 6^3), you can use the property of exponents that states (a^m \times a^n = a^{m+n}). In this case, you add the exponents: (2 + 3 = 5). Therefore, (6^2 \times 6^3 = 6^5).
8m - 1/4
m^4 n^5 - m^20 n^21
It is not possible to answer the question because different books number number the laws differently.