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m^4 x m^3 = m^7
Using a numerical example, 2^4 x 2^3 = 16 x 8 = 128 = 2^7
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∙ 14y ago
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What is M to the fourth power Times n to the fourth power?
m4n4
X to the third power times x to the fourth power?
X to the 7th power. X^m*X^n=X^m+n That means when you multiply variables with the same base, you add the exponents.
What is the fourth root of 125 m times the fourth root of 35?
8.13288 (rounded)
How would you write an verbal expression for 4m to the fourth power?
Four times a variable, named m, multiplied by itself four times. Technically (or pedantically) it is multiplied three times but that is one of the oddities of verbal expressions.
How do you solve M to the power of 4 times N to the power of 5 minus M to the power of 20 times N to the power of 21 m4 n5 - m20n21?
m^4 n^5 - m^20 n^21
What is M to the fourth power Times n to the fourth power?
m4n4
X to the third power times x to the fourth power?
X to the 7th power. X^m*X^n=X^m+n That means when you multiply variables with the same base, you add the exponents.
What does m to the third power mean?
What does m times m times m mean?
What is the answer to -2m to the fourth power times n to the 6thpower to the 2nd power?
The question is open to multiple interpretations but I think you mean [(-2m)^4] x (n^6)^2 = [(-2)^4](m^4)(n^12) = 16(m^4)(n^12) or 16 times m to the 4th power times n to the 12th power.
What is m to the third power plus 125n to the third power?
m3 + 125n3 = (m + 5n)*(m2 - 5mn + 25n2)
What is the fourth root of 125 m times the fourth root of 35?
8.13288 (rounded)
How would you write an verbal expression for 4m to the fourth power?
Four times a variable, named m, multiplied by itself four times. Technically (or pedantically) it is multiplied three times but that is one of the oddities of verbal expressions.
How do you solve M to the power of 4 times N to the power of 5 minus M to the power of 20 times N to the power of 21 m4 n5 - m20n21?
m^4 n^5 - m^20 n^21
Subtract one fourth from 8 times m?
8m - 1/4
What does M to the second power equal?
The "second power" means squared. "Squared" means multiplied by itself. Thus M to the second power = M times M.
How do you solve a to the power of m times a to the power of n?
am * an = am+n
What is m to the power of 3 times m to the power of 5?
m3*m5 = m3+5 = m8
