(Force*Time2 )/m = distance
Make sure units correct
You would have a very tough time, because that isn't the formula to calculate work. (distance) divided by (time) is the formula to calculate speed. The formula to calculate work is: (force) multiplied by (distance).
Power = (work) divided by (time) If you don't know the amount of work, you can calculate it. Work = (force) times (distance).
The dimension of power is (energy / time)= (force x distance) / time= (mass x distance / time2) x distance / time= mass x distance2 / time3= ML2T-3
You can't because you need the time involved. Force x distance shifted in the direction of the force = energy. But power is energy per unit time (seconds etc)
F = a + bxWe're told that 'F' is force and 'x' is distance. So both of the terms 'a' and 'bx'are also force.Dimensionally:[ a ] = [ force ] = [ mass - length3 - time-2 ][ b ] = [ force/length ] = [ mass - length2 - time-2 ]
You calculate peak force by multiplying Mass times Velocity divided by time
(mass X distance)/(time X time), or mass times acceleration
Well, let's see . . .[ pressure ] x [ mass / time ] = [ force / area ] x [ mass / time ] = [ force ] x [ mass / area-time ][ Energy ] = [ force ] x [ distance ]There's no way that [ mass / area-time ] is equal to [ distance ],so the answer is pretty clearly 'no' .
you divide distance over time
You would have a very tough time, because that isn't the formula to calculate work. (distance) divided by (time) is the formula to calculate speed. The formula to calculate work is: (force) multiplied by (distance).
Time, velocity and mass do not provide enough information. If you are given a time interval, t, then you need the velocity at the start of the interval (= u) and at its end (v). Then F = m*(v - u)/t
Pressure is defined as the amount of force applied to a given amount of area. Therefore pressure is derived from force and distance. Force itself is derived from time, distance, and mass and area is derived from distance.
Power = (work) divided by (time) If you don't know the amount of work, you can calculate it. Work = (force) times (distance).
The dimension of power is (energy / time)= (force x distance) / time= (mass x distance / time2) x distance / time= mass x distance2 / time3= ML2T-3
No. That's only one of several possibilities. -- with initial velocity, distance, and time, you can calculate acceleration -- with final velocity, distance, and time, you can calculate acceleration -- with force and mass, you can calculate acceleration -- with initial and final momentum, you can calculate acceleration -- with initial and final kinetic energy, you can calculate acceleration -- with mass, velocity at either end, and kinetic energy at the other end, you can calculate acceleration And I'm sure there are several more that I've missed.
To calculate the velocity we would have to know the mass of the first object because we need it to find the force of gravity between the two bodies to then find out the net distance and time.
Work is force times distance. A Force divided by Distance: looking at the units, Force = newtons = kg m / s^2 = mass x length / time^2 so ML/T^2 Distance = m = length so L Force/Distance = (ML/T^2)/L = ML/LT^2 = M/T^2 So the units of a force divided by distance are mass/ time^2 This would be the rate of change of mass change with respect to time.