i dont know that's why I'm asking
The equation used to calculate the distance something travels is given below . we know, speed = distance /time . distance = speed X time in meters /km /or any other unit of length.
You calculate the coordinates using a fraction!
By checking how deep the rope is in the water.
Find (or calculate) the equation of the line. Select any value of x. Calculate the corresponding value for y using the equation. Then (x, y) is a point on the same line.
A dimensional check in an equation can provide a quick check about the possible correctness of the equation. For example, if you are supposed to calculate a speed, the dimensions of the result MUST be of the form [distance] / [time] (or something that you can simplify to distance/time). If it doesn't, the formula is wrong. If it does, it MIGHT be correct.
Distance divided by speed is used to calculate time.
The equation used to calculate the distance something travels is given below . we know, speed = distance /time . distance = speed X time in meters /km /or any other unit of length.
Work = Force * work=Force x Distance
You calculate the coordinates using a fraction!
You can calculate the tangent for a give time, T, as follows: Substitute the value of the time in the distance-time equation to find the distance at the given time. Suppose it is f(T). Differentiate the distance-time equation with respect to time. For any given time, substitute its value in the derivative and evaluate. That is the gradient of the tangent, v. Then equation of the tangent is f(T) - f(t) = v*(T - t)
By checking how deep the rope is in the water.
Find (or calculate) the equation of the line. Select any value of x. Calculate the corresponding value for y using the equation. Then (x, y) is a point on the same line.
The equation to calculate the work done is: Work done (J) = force applied (n) x distance moved of force (m)
A dimensional check in an equation can provide a quick check about the possible correctness of the equation. For example, if you are supposed to calculate a speed, the dimensions of the result MUST be of the form [distance] / [time] (or something that you can simplify to distance/time). If it doesn't, the formula is wrong. If it does, it MIGHT be correct.
Distance divided by speed will give you the time it took to travel the distance.
by using the equation k=LN(present#/pats #)/(t2-t1).
yes we can calculate it by using trigonometric equation (by finding tan θ).